All categories

3 years ago

By what factor does the drag force on a car increase as it goes from 65 to 110 km/h?

Physics

2 answers:

GrogVix [38]3 years ago

5 0

Answer:

The drag force is increase by 2.9

Explanation:

The drag force on the car is:

$F_{drag} =\frac{1}{2} pCAv^{2}$

Where p is the density, A is the area of the car facing the air, C is the drag coefficient and v is the velocity. If k=(pCA)/2, then we have:

Fdrag=kv^2

For the speed 65 km/h:

Fdrag1=k(65^2)

For the speed 110 km/h

Fdrag2=k(110^2)

The ratio is:

Ratio=Fdrag2/Fdrag1=(k*65^2)/(k*110^2)=2.9

Art [367]3 years ago

3 0

I=2.86 HOPE I HELPED

You might be interested in

1.Which car has zero acceleration?<br><br>2. which car is decelerating?

Ivanshal [37]

Answer:

1. B has no acceleration because the straight line shows that it's a constant speed not speeding up or down.

2. A because you can see the decline in speed as time goes on

5 0

3 years ago

3. What are the challenges of looking for Dyson spheres?

S_A_V [24]

1. it is difficult to search for it . Because infrared rays will never penetrate through earth atmosphere.

2. we are unaware of how it looks like and we only know it is red and will glow . A damaged star also looks like this.

3. Dust also makes is hard to detect Dyson spheres . So we will get confused between Dyson sphere and a star surrounded by dust.

5 0

3 years ago

Read 2 more answers

Suppose you want to test the hypothesis that plants grow taller when they receive more sunlight. Identify and independent variab

ollegr [7]

The result that should be established is in the form
y = f(x)
where x, the amount of sunlight is the controlled (independent) variable,
y = height (growth) that corresponds to the amount of sunlight. Therefore y depends on x.

Clearly,
x, the amount of sunlight is the independent variable. It can be controlled.
y, the measured amount of growth is the dependent variable.

Answer:
The independent variable is the amount of sunlight.
The dependent variable is the growth.

5 0

4 years ago

A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou

Whitepunk [10]

Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

$\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m$

$\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s$

State 2 : constant speed

$\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m$

State 3 : deceleration

$\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)$

$\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m$

Total distance : state 1+ state 2+state 3

$\tt 200 + 36000 + 300=36500~m$

the average velocity = total distance : total time

$\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s$

4 0

3 years ago

If an object moving at 12 m/s has a kinetic energy of 72 j what is the mass

EleoNora [17]

Simply, apply the formula $E = \frac{1}{2}mv^{2}$ and insert the values of m = mass, v = velocity and E = Energy.
The result will be $72J = \frac{1}{2}m(12m/s)^{2}$ , m = 1 kg

5 0

3 years ago