By what factor does the drag force on a car increase as it goes from 65 to 110 km/h?
2 answers:
Answer:
The drag force is increase by 2.9
Explanation:
The drag force on the car is:
Where p is the density, A is the area of the car facing the air, C is the drag coefficient and v is the velocity. If k=(pCA)/2, then we have:
Fdrag=kv^2
For the speed 65 km/h:
Fdrag1=k(65^2)
For the speed 110 km/h
Fdrag2=k(110^2)
The ratio is:
Ratio=Fdrag2/Fdrag1=(k*65^2)/(k*110^2)=2.9
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expression of Kinetic energy of rotating body
ω = 34.0 rad/s
Assuming mass of the particle equal to 13 Kg
and perpendicular distance from the particle to the axis is r = 1.25 m
now,
moment of inertia of particle = ?
from the given expression
..............(1)
we know
v = r ω
putting value in equation (1)
I = 20.3125 kg.m²