1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Firdavs [7]
3 years ago
8

By what factor does the drag force on a car increase as it goes from 65 to 110 km/h?

Physics
2 answers:
GrogVix [38]3 years ago
5 0

Answer:

The drag force is increase by 2.9

Explanation:

The drag force on the car is:

F_{drag} =\frac{1}{2} pCAv^{2}

Where p is the density, A is the area of the car facing the air, C is the drag coefficient and v is the velocity. If k=(pCA)/2, then we have:

Fdrag=kv^2

For the speed 65 km/h:

Fdrag1=k(65^2)

For the speed 110 km/h

Fdrag2=k(110^2)

The ratio is:

Ratio=Fdrag2/Fdrag1=(k*65^2)/(k*110^2)=2.9

Art [367]3 years ago
3 0

I=2.86     HOPE I HELPED


You might be interested in
A 3.9 kg block is pushed along a horizontal floor by a force of magnitude 30 N at a downward angle θ = 40°. The coefficient of k
Luba_88 [7]

Answer:

The frictional force  F_{fri} = 6.446 N

The acceleration of the block a = 6.04 \frac{m}{s^{2} }

Explanation:

Mass of the block = 3.9 kg

\theta = 40°

\mu = 0.22

(a). The frictional force is given by

F_{fri} = \mu R_{N}

R_{N} = mg \cos \theta

R_{N} = 3.9 × 9.81 × \cos 40

R_{N} = 29.3 N

Therefore the frictional force

F_{fri} = 0.22 × 29.3

F_{fri} = 6.446 N

(b). Block acceleration is given by

F_{net} = F - F_{fri}

F = 30 N

F_{fri} = 6.446 N

F_{net} = 30 - 6.446

F_{net} = 23.554 N

The net force acting on the block is given by

F_{net}  = ma

23.554 = 3.9 × a

a = 6.04 \frac{m}{s^{2} }

This is the acceleration of the block.

8 0
3 years ago
A 50.0 kg object rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300 and
MariettaO [177]

Answer:

f=140\ N

Explanation:

Given:

  • mass of the object on a horizontal surface, m=50\ kg
  • coefficient of static friction, \mu_s=0.3
  • coefficient of kinetic friction, \mu_k=0.2
  • horizontal force on the object, F=140\ N

<u>Now the value of limiting frictional force offered by the contact surface tending to have a relative motion under the effect of force:</u>

F_s=\mu_s.N

where:

N= normal force of reaction acting on the body= weight of the body

F_s=0.3\times (50\times 9.8)

F_s=147\ N

As we know that the frictional force acting on the body is always in the opposite direction:

So, the frictional force will not be at its maximum and will be equal in magnitude to the applied external force and hence the body will not move.

so, the frictional force will be:

f=140\ N

8 0
3 years ago
How fast is a wave traveling if it has a wavelength of 7 meters and a frequency of 11 Hz?
pashok25 [27]

Answer:

\huge{ \boxed{ \bold{ \sf{77 \: m/s}}}}

☯ Question :

  • How fast is a wave travelling if it has a wavelength of 7 meters and a frequency of 11 Hz?

☯ \underbrace{ \sf{Required \: Answer  :  }}

☥ Given :

  • Wavelength ( λ ) = 7 meters
  • Frequency ( f ) = 11 Hz

☥ To find :

  • Speed of sound ( v ) = ?

☄ We know ,

\boxed{ \sf{v = f \times λ}}

where ,

  • v = speed of sound
  • f = frequency
  • λ = wavelength

Now, substitute the values and solve for v.

➺ \sf{v = 11 \times 7}

➺ \boxed{ \sf{v = 77 \: m/s}}

-------------------------------------------------------------------

✑ Additional Info :

  • Frequency : The number of complete vibrations made by a particle of a body in one second is called it's frequency. It is denoted by the letter f . The SI unit of frequency is hertz ( Hz ).

  • Wavelength : The distance between two consecutive compressions or rarefactions of a sound wave is called wavelength of that wave. It is denoted by λ ( lambda ) and it's SI unit is m.

  • Speed of a sound wave : The distance covered by a sound wave in one second is called speed of sound wave. It depends on the product of wavelength and frequency of the wave.

Hope I helped!

Have a wonderful time! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

7 0
3 years ago
Eukaryotic cells can be unicellular and multicellular true or false
dimaraw [331]
Yes, it can be unicellular and multicellular
8 0
3 years ago
Hooke's law describes a certain light spring of unstretched length 31.8 cm. when one end is attached to the top of a doorframe a
lubasha [3.4K]

Answer:

Explanation:

extension in the spring = 40.4 - 31.8 = 8.6 cm = 8.6 x 10⁻² m .

kx = mg

k is spring constant , x is extension , m is mass

k x 8.6 x 10⁻² = 7.52 x 9.8

k = 856.93 N/m

=  857 x 10⁻³ KN /m

b ) Both side is pulled by force of 188 N .

Tension in spring = 188N

kx = T

856.93 x = 188

x = .219.38 m

= 21.938 cm

= 21.9 cm .

length of spring = 31.8 + 21.9

= 53.7 cm .

6 0
2 years ago
Other questions:
  • What happens during the apparent retrograde motion of a planet?
    14·1 answer
  • CO2 , NaCl , HCl can be classified as ?
    8·1 answer
  • 1. in which lover of Earth are temperature and<br> pressure greatest?<br> 1-A<br> B <br> C <br> D
    11·1 answer
  • An egg is cracked/broken. Is this egg experiencing a Physical or Chemical change? (Hint: is it still an egg?)
    7·1 answer
  • What are the two factors that determine the strength of the force of friction
    11·1 answer
  • Calculate the density of an object with a volume of 18m3 and a mass of 3.5kg?
    5·1 answer
  • heather and matthew walk with an average velocity of 98 m/s eastward. If it takes them 34 min ro walk to the store, what is thei
    9·1 answer
  • Plateau period are times in life when
    13·1 answer
  • An athlete runs four laps of a 400 m track. What is the athlete's total displacement?​
    14·1 answer
  • Vector A⃗ points in the negative y direction and has a magnitude of 5 km. Vector B⃗ has a magnitude of 15 km and points in the p
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!