Question

By what factor does the drag force on a car increase as it goes from 65 to 110 km/h?

Answer 1

Answer:

The drag force is increase by 2.9

Explanation:

The drag force on the car is:

$F_{drag} =\frac{1}{2} pCAv^{2}$

Where p is the density, A is the area of the car facing the air, C is the drag coefficient and v is the velocity. If k=(pCA)/2, then we have:

Fdrag=kv^2

For the speed 65 km/h:

Fdrag1=k(65^2)

For the speed 110 km/h

Fdrag2=k(110^2)

The ratio is:

Ratio=Fdrag2/Fdrag1=(k*65^2)/(k*110^2)=2.9

Answer 2

I=2.86     HOPE I HELPED