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irina1246 [14]
4 years ago
8

The law of suggests that the orbit of planets is not circular but .

Physics
2 answers:
SVEN [57.7K]4 years ago
3 0
One of Kepler's laws is that the orbits of planets are elliptical. It's not a suggestion. BTW, circles are ellipses too, but so special that their likelihood is close to zero.
makkiz [27]4 years ago
3 0

Answer:

Kepler's first law suggests that the orbit of planets is not circular but elliptical

Explanation:

The three Kepler's laws explain the motion of the planets orbiting the Sun:

- The first law tells that the orbits of the planets around the Sun are ellipses, with the Sun located at one of the two focii

- The second law tells that a line connecting the Sun with the planet sweeps out equal areas in equal amounts of time

- The third law tells that the square of the orbital periods of the planets is proportional to the cube of their average distance from the Sun

As we can read, the first law tells us that the orbit of the planets is not circular, but elliptical.

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Energy

Explanation:

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3 years ago
The tendency of an object to resist any change in its motion is known as?
kvv77 [185]
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7 0
3 years ago
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A spherically-spreading EM wave comes from a 104.0 W source. At a distance of 9.6 m, what is the intensity of the wave?
Nookie1986 [14]

Answer:

Approximately 0.0898 W/m².

Explanation:

The intensity of light measures the power that the light delivers per unit area.

The source in this question delivers a constant power of \rm 104.0\; W. If the source here is a point source, that \rm 104.0\; W of power will be spread out evenly over a spherical surface that is centered at the point source. In this case, the radius of the surface will be 9.6 meters.

The surface area of a sphere of radius r is equal to 4\pi r^{2}. For the imaginary 9.6-meter sphere here, the surface area will be:

\rm 4\pi \times (9.6\; m)^{2} \approx 1158.12\; m^{2}.

That \rm 104.0\; W power is spread out evenly over this 9.6-meter sphere. The power delivered per unit area will be:

\displaystyle\rm  \frac{104.0\; W}{1158.12\; m^{2}}\approx 0.0898\; W\cdot m^{-2}.

8 0
3 years ago
Two cars are initially separated by 2500 m and traveling towards each other. One car travels at 4.5 m/s and the second car trave
mylen [45]

Answer:

714.285s

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use relative velocity

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7 0
3 years ago
Hi, Solve for λ<br> E=hc/λ
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Answer:

λ=hc/E

Explanation:

E=hc/λ

Eλ=hc

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4 0
3 years ago
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