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3 years ago

The law of suggests that the orbit of planets is not circular but .

2 answers:

3 0

One of Kepler's laws is that the orbits of planets are elliptical. It's not a suggestion. BTW, circles are ellipses too, but so special that their likelihood is close to zero.

makkiz [27]3 years ago

3 0

Answer:

Kepler's first law suggests that the orbit of planets is not circular but elliptical

Explanation:

The three Kepler's laws explain the motion of the planets orbiting the Sun:

- The first law tells that the orbits of the planets around the Sun are ellipses, with the Sun located at one of the two focii

- The second law tells that a line connecting the Sun with the planet sweeps out equal areas in equal amounts of time

- The third law tells that the square of the orbital periods of the planets is proportional to the cube of their average distance from the Sun

As we can read, the first law tells us that the orbit of the planets is not circular, but elliptical.

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2 years ago

What is the minimum runway length that will serve? hint: you can solve this problem using ratios without having any additional i

ehidna [41]

There are many factors that determine if an aircraft can operate from a given airport. Of course the availability of certain services, such as fuel, access to air stairs and maintenance are all necessary. But before considering anything else, one must determine if the plane can physically land at an airport, and equally as important, take off.

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Looking at aerial views of runways can lead some to the assumption that they are all uniform, big and appropriate for any plane to land. This couldn’t be further from the truth.

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2 years ago

A basketball player shoots toward a basket 5.3 m away and 3.0 m above the floor. If the ball is released 1.9 m above the floor a

Snezhnost [94]

Answer:

Vi = 8.28 m/s

Explanation:

This problem is related to the projectile motion.

As we know there are two components of motion associated with this, the horizontal component and vertical component.

The horizontal distance covered by the ball is

Vx*t = x

Vx*t = 5.3

Vx = 5.3/t eq. 1

Also we know that

Vx = Vicos(60)

Vx = Vi*0.5 eq. 2

equate eq. 1 and eq. 2

5.3/t = Vi*0.5

5.3/0.5 = Vi*t

Vi*t = 10.6 eq. 3

The vertical distance is

Vy = y1 + Vyi*t - 0.5gt²

also we know that

Vyi = Visin(60)

Vyi = Vi*0.866

It is given that V1 = 1.9 m and and Vy = 3 m is the vertical distance

3 = 1.9 + Vi*0.866*t - 0.5gt²

3 = 1.9 + Vi*0.866*t - 0.5(9.8)t²

3 = 1.9 + 0.866(Vi*t) - 0.5(9.8)t²

1.1 = 0.866(Vi*t) - 4.9t²

0.866(Vi*t) = 4.9t² + 1.1

substitute Vi*t = 10.6 in above equation

0.866(10.6) = 4.9t² + 1.1

9.18 = 4.9t² + 1.1

4.9t² = 8.08

t² = 8.08/4.9

t² = 1.648

t = 1.28 sec

Finally, initial speed can be found by substituting the value of t into eq. 3

Vi*t = 10.6

Vi = 10.6/t

Vi = 10.6/1.28

Vi = 8.28 m/s

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3 years ago

You are given an unknown liquid and asked to determine its identity. You can measure only one physical property. You decide to h

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B boiling point because you used heat and it turned to vapor so it was boiled

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