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2 years ago

13

What happens to the velocity of a sound wave in air if the temperature of the air increases?

2 answers:

Yuki888 [10]2 years ago

6 0

The answer is D :) hope this helps

Burka [1]2 years ago

5 0

Decreases ( no B is answer)

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Explain why greenhouse gases in the atmosphere cause an increase in temperature?

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Any gas in the atmosphere that absorbs and emits thermal infrared radiation is referred to as a greenhouse gas (GHG). These are the primary causes of the greenhouse effect, which causes the Earth's temperature to rise. Earth is warmer because less heat radiates into space.

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2 years ago

What is the answer I’m stuck on this one it’s a screenshot for the question

Dmitry_Shevchenko [17]

Answer:

deceleration is the opposite of acceleration

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2 years ago

The watermark can be of different types depending on the application. A watermark will resist manipulations of the media. Howeve

Marina86 [1]

<em>The first blank is </em><em>robust watermark</em>; a robust watermark will not resist tampering.

<em>The second blank is </em><em>fragile watermark</em><em>;</em> a fragile watermark will resist manipulations of the media.

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A robust watermark will not resist tampering.
A fragile watermark will resist manipulations of the media.

Thus, The first blank is robust watermark; a robust watermark will not resist tampering.

The second blank is fragile watermark; a fragile watermark will resist manipulations of the media.

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1 year ago

The alternating current which crosses an apparatus of 600 W has a maximum value of 2.5 A. What is efficient voltage between its

azamat

Answer: Option (b) is correct.

Explanation:

Since we know that,

P = VI

where;

P = power

V= Voltage

I = Current

Since it's given that,

P = 600W

I = 2.5 A

equating these values in the above equation, we get;

<em>V = $\frac{600}{2.5}$ </em>

<em>V = 240 V</em>

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3 years ago

An air balloon is moving upward at a constant speed of 3 m/s. Suddenly a passenger realizes that she left her camera on the grou

frosja888 [35]

Answer:t=0.3253 s

Explanation:

Given

speed of balloon is $u=3\ m/s$

speed of camera $u_1=20\ m/s$

Initial separation between camera and balloon is $d_o=5\ m$

Suppose after t sec of throw camera reach balloon then,

distance travel by balloon is

$s=ut$

$s=3\times t$

and distance travel by camera to reach balloon is

$s_1=ut+\frac{1}{2}at^2$

$s_1=20\times t-\frac{1}{2}gt^2$

Now

$\Rightarrow s_1=5+s$

$\Rightarrow 20\times t-\frac{1}{2}gt^2 =5+3t$

$\Rightarrow 5t^2-17t+5=0$

$\Rightarrow t=\dfrac{17\pm \sqrt{17^2-4(5)(5)}}{2\times 5}$

$\Rightarrow t=\dfrac{17\pm 13.747}{10}$

$\Rightarrow t=0.3253\ s\ \text{and}\ t=3.07\ s$

There are two times when camera reaches the same level as balloon and the smaller time is associated with with the first one .

(b)When passenger catches the camera time is $t=0.3253\ s$

velocity is given by

$v=u+at$

$v=20-10\times 0.3253$

$v=16.747\ m/s$

and position of camera is same as of balloon so

Position is $=5+3\times 0.3253$

$=5.975\approx 6\ m$

8 0

3 years ago