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andrew11 [14]
4 years ago
9

A glass is half-full of water, with a layer of vegetable oil (n 5 1.47) fl oating on top. a ray of light traveling downward throu

gh the oil is incident on the water at an angle of 71.48. determine the critical angle for the oil–water interface and decide whether the ray will penetrate into the water.
Physics
1 answer:
leva [86]4 years ago
6 0
The critical angle is the angle of incidence which gives 90 degrees refraction of light. If the incident angle is less than the critical angle, the ray of light will penetrate the second medium and if the incident angle is more than the critical angle, the ray will not penetrate and total internal reflection will occur.

So, to decide whether the ray will penetrate or not, we need to calculate the critical angle and compare it with the incident angle.

critical angle is calculated using the following rule:
critical angle = arcsin (n2 / n1) where
n1 is that of the oil = 1.47
n2 is that of the water = 1.33
therefore,
critical angle =  arcsin (1.33 / 1.47) = 64.79 degree

Since the incident angle is greater than the critical angle, therefore the ray will not penetrate and will undergo total internal reflection.
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Choose all the answers that apply.
slava [35]
<h2>So, the correct answers are:</h2>

Travels in longitudinal waves

Travels most slowly through a gas

Speeds up when temperature is increased

Is caused by vibration

Explanation for correct answers:

Yes, it does travel in longitudinal waves

Yes, sounds weird, but travels faster in the water

Yes, does speed up when temperature is increased

And yes, Is caused by vibration.

<h2>Wrong answer is:</h2>

Can travel through a vacuum

Explanation for wrong answer:

actually, in space, there is NO sound, because there are no particals for the sound to vibrate with, there's just empty SPACE.

5 0
3 years ago
Design a modified priority encoder that receives an 8-bit input, A7:0and produces a 3-bit output, Y2:0. Y indicates the most sig
cupoosta [38]

Answer:

Explanation:

The first image that I attached to this solution is the diagram of a truth table for an 8 to 3 bit encoder.

The second image  gives a sketch of the schematic.

The Boolean expression for the priority encoder including its zero inputs is defined in the third image attached.

Below is a snippet of the code for an 8 to 3 bit Priority encoder:

library IEEE;

use IEEE.STD_LOGIC_1164.all;

entity encoder8_3 is

   port(

       din : in STD_LOGIC_VECTOR(7 downto 0);

       dout : out STD_LOGIC_VECTOR(2 downto 0)

        );

end encoder8_3;

architecture encoder8_3_arc of encoder8_3 is

begin

   dout <= "000" when (din="10000000") else

           "001" when (din="01000000") else

           "010" when (din="00100000") else

           "011" when (din="00010000") else

           "100" when (din="00001000") else

           "101" when (din="00000100") else

           "110" when (din="00000010") else

           "111";

end encoder8_3_arc;

3 0
3 years ago
Describe 3 uses of radioactive isotopes
pantera1 [17]
Cancer treatments, Radiography, food irradiation
8 0
2 years ago
Read 2 more answers
A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp
lubasha [3.4K]

Answer:

a) 915 m

b) 0.15 W/m^{2}

Explanation:

solution:

a) The wavelength of the microwaves electromagnetic wave is:

λ=\frac{c}{f}=\frac{3*10^{8} }{12*10^{9}}=0.025 m

the circular radar antenna acts like a circular aperture of diameter D will have a bright central maximum of diameter:

w=2.44λL/D

so at 30 km screen:

w=2.44λL/w

  =2.44*0.025*30*10^3/2

  =915 m

b)

The area of a beam at 30 km is:

A=\pi  r^{2}=\pi (\frac{w}{2} )^2=\pi (\frac{915}{2} )^2=657*10^{3} m^{2}

the average microwave intensity is equal to the ratio of the power of the antenna and area of the beam:

I=P/A

So at 30 km:

I=100*10^3/657*10^3

=0.15 W/m^{2}

8 0
3 years ago
A city planner is working on the redesign of a hilly portion of a city. An important consideration is how steep the roads can be
Artyom0805 [142]

Explanation:

It is known that relation between force and acceleration is as follows.

                      F = m \times a

I is given that, mass is 1090 kg and acceleration is 21 m/s. Therefore, we will calculate force as follows.

              F = m \times a      

                 = 1090 \times (\frac{21}{16})

                 = 1430.625 N

Also, it is known that

      sin(\theta) = \frac{\text{Force car can exert}}{\text{Force gravity pulls car}}

      sin(\theta) = \frac{1430.625 N}{(1090 \times 9.8) N}

        \theta = 7.70 degrees

Thus, we can conclude that the maximum steepness for the car to still be able to accelerate is 7.70 degrees.

8 0
3 years ago
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