Option (a) is correct.
Falling objects accelerate as they approach the ground.This is because of the force of gravity acting on the falling objects. so the velocity of these objects increases continuously as they approach the ground. the acceleration acting on the falling objects is a constant ( close to the surface of earth) and is called as acceleration due to gravity denoted by g. value of g=9.8 m/s².
It is electrical energy into connected energy has in relation to the question
Answer:
Charge of particle 2, 
Explanation:
Given that,
Charge 1, 
The distance between charges, r = 0.241 m
Force experienced by particle 1, F = 3.44 N
We need to find the magnitude of electric charge 2. It can be calculated using formula of electrostatic force. It is given by :
or
So, the magnitude of electric charge 2 is . Since, the force is attractive then the magnitude of charge 2 must be negative.
(1,500 meters) x (1 sec/330 meters) =
(1,500 / 330) (meters-sec/meters) =
4.55 seconds
Answer:
initial velocity = 0 m/s
final velocity = 4.92 m/s
constant acceleration so,
(a) average velocity =
(initial velocity + final velocity)/2
(b) distance = average velocity x time
substitute and calculate
Explanation:
HOOE ITS HELP ;)
