Answer:
40 Grams
Explanation:
Fe2O3 is 2 parts Iron 3 parts Oxygen.
Assuming the molecular weights of both are equivalent (<em>ideal elemental law</em>), it is a 2:3 ratio, or 2/5 of the total.
2/5 of 100 is 40, so the answer is
40 grams
Kr, Ar, Ne, N
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Compounds have the lowest percentage of gold content by weight is <u>Aui3</u>
M(Au) =197g/mol
M(O) =16g/mol
M(H)=1g/mol
M(Cl)=35g/mol
M(I)=53 g/mol
1) M=214g/mol =197+1+16
197/214= 0.921
2) M=248g/mol =
197/248=0.794
3) M=302g/mol =
197/302=0.652
4) M=356g/mol =
197/356=0.5533
<u>Explanation:</u>
Iodine is the heaviest out of I, Cl and OH. The items on your list hold less and less gold by mass as you go down. The gold dissolution percentage in a hypochlorite-iodide mix-up is completely conditioned upon the solution pH. So the iodine has the lowest gold content percentage.
Answer:
energy required is 0.247kJ
Explanation:
The formula to use is Energy = nRdT;
Where n is number of mole
R is the molar gas constant
dT is the change in temperature
n = reacting mass of mercury / molar mass of mercury = 27.4/200.59 = 0.137
dT = final temperature - initial temperature = 376.20 - 158.30 = 217.90K
R = 8.314Jper mol per Kelvin
Energy = 0.137 x 8.314 x 217.90 = 247.12J
Energy in kJ= 247.12/1000= 0.247kJ
The first step is to convert the 55 kg of Fe₃O₄ to moles by using the molar mass, that is, 231.55 g/mol (55 kg = 55000 gms),
55000 gms × 1 mole / 231.55 gms = 237.53 moles of Fe₃O₄
For the decomposition of every 1 mole of Fe₃O₄, +1118 kJ of energy is needed. Therefore, the energy needed to decompose 237.53 moles will be:
237.53 moles of Fe₃O₄ × 1118 kJ / 1 mole = 265558 kJ
Thus, there is a need of 265558 kJ of energy to decompose 55 kg of Fe₃O₄.