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Finger [1]
3 years ago
13

Can someone help me please. I accidentally clicked that answer so im not sure if its correct

Chemistry
1 answer:
alexandr402 [8]3 years ago
8 0
I think it is, not sure
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For H3PO4, Ka1 = 7.3 x 10^-3, Ka2 = 6.2 x 10^-6, and Ka3 = 4.8 x 10^-13. A 0.10 M aqueous solution of Na3PO4 therefore would be
zmey [24]

Answer:

The aqueous solution of Na_{3} Po_{4} therefore would be "strongly basic."

Explanation:

Strongly basic because the Na_{3} Po_{4} is completely an ionic compound. These compound can be 100% splitted into metal ions and hydroxide ion when used in the aqueous solution. Each moles dissolves which can give rise to mole of hydrogen ions when used in the solution. Whereas strong bases are not soluble in water as well.  in the presence of water equilibrium can also be achieved. A strong base has the capability which can just remove the proton from the molecule.

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3 years ago
Examining a corpse, you find many second instars and a few third instars on the body and moving away from it You find no pupae i
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I don't know maybe 50 and 72 hours?

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3 years ago
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A gas has a volume of 5.00 L at 20 degrees Celsius. What is the volume of gas at 150 degrees Celsius.
WARRIOR [948]

Answer:

7.22 L

Explanation:

From the question,

Applying Charles law,

V₁/T₁ = V₂/T₂...................... Equation 1

Where V₁ = Initial volume of gas, V₂ = Final volume of gas, T₁ = Initial Temperature of gas in Kelvin, T₂ = Final Temperature of gas in Kelvin

Make V₂ the subject of the equation

V₂ = (V₁×T₂)/T₁................. Equation 2

Given: V₁ = 5.00 L, T₁ = 20 °C = (20+273) K = 293 K, T₂ = 150 °C = (150+273) K = 423 K

Substitute these value into equation 2

V₂ = (5.00×423)/293

V₂ = 7.22 L

5 0
3 years ago
Titanium(IV) chloride decomposes to form titanium and chlorine, like this:
Lesechka [4]

The full question is shown in the image attached to this answer

Answer:

6.2 * 10^-3

Explanation:

The reaction at equilibrium is as follows;

TiCl4(l) → Ti(s)+ 2Cl2(g)

We have to obtain the concentration of chlorine gas as follows;

[Cl2] = 1.08/70.91 g/mol × 5.2 L

[Cl2] = 0.079 M

Kc = [Cl2]^2

Kc = [ 0.079]^2

Kc = 6.2 * 10^-3

4 0
3 years ago
What is acnsrl spgei
joja [24]
Spring scale
It's a tool used to measure force.

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3 years ago
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