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Lisa [10]
2 years ago
6

A very long half-cylinder of radius r carries a total current is uniformly distributed across the circumference. Determine the m

agnetic field along the central axis of the cylinder.
Physics
1 answer:
Rufina [12.5K]2 years ago
8 0

The magnetic field along the central axis of the cylinder will be <em>determined </em>using the formula given that all parameters are known

dBz=\frac{uoR^2di}{2r^3}

<h3>Magnetic field </h3>

Generally, A magnetic field is also referred to as a vector field that shows the magnetic presence on electric charges and magnetic materials.

The formula for magnetic field  is

Where

u=4\pi*10^{-7H/M}

Therefore, the magnetic field along the central axis of the cylinder will be determined using the formula given that all parameters are known

For more information on Magnets

brainly.com/question/7802337

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Since it is spherical, so

 Volume=(4/3)*pi*r^3

V= (4/3)*pi*(50*10^-6)^3

V=5.23599*10^-13 m^3

 

We are given the Density(ρ) =2600kg/m^3

 

We know that:

Density(p) = mass(m)/volume(V)

m = ρV

 

So the mass of a single grain is:

m = 5.23599*10^-13 * 2600 = 1.361357*10^-9 kg

 

 

The surface area of a grain is:

a = 4*pi*r^2

a = 4*pi*(50*10^-6)^2

a = 3.14*10^-8 m^2

 

 

Since we know the surface area and mass of a grain, the conversion factor is:

1.361357*10^-9 kg / 3.14*10^-8 m^2

 

Find the Surface area of the cube:

cube = 6a^2

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multiply this by the converions ratio to get:

total mass of sand grains = (7.26 m^2 * 1.361357*10^-9 kg) / (3.14*10^-8 m^2)

total mass of sand grains = 0.3148 kg = 314.80 g

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