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3 years ago

60 kilometers in 4 hours, what is the average speed?

Physics

1 answer:

allsm [11]3 years ago

8 0

Average speed = (distance covered) / (time to cover the distance)

Average speed = (60 kilometers) / (4 hours)

Average speed = (60/4) kilometer/hour

<em>Average speed = 15 km/hr</em>

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An electron and a proton have charges of an equal magnitude but opposite sign of 1.60 10-19 C. If the electron and proton in a h

MA_775_DIABLO [31]

The proton's electrostatic force exerted on the electron will be 3.5×10¹² N.

<h3>What is the electrostatic force?</h3>

It is a force imposed by one charge on another as a result of the field.

The electrostatic force produced by one line charge on another line charge separated by r is determined by the charge potency of each charge as well as the separation distance between them.

The electrostatic force is found as:

$\rm F= \frac{Kq_1q_2}{R^2} \\\\ F= \frac{9 \times 10^ 9 \times 1.6 \times 10^{-19} \times -1.6 \times 10^{-19} }{(2.00\times 10^{-11})^2} \\\\\ F= 3.5 \times 10^{12} \ N$

Hence, the proton's electrostatic force exerted on the electron will be 3.5×10¹² N.

To learn more about the electrostatic force refer to the link;

brainly.com/question/9774180

#SPJ1

8 0

2 years ago

Two small identical conducting spheres are placed with their centers 0.41 m apart. One is given a charge of 12 ✕ 10−9 C, the oth

nataly862011 [7]

(a) $-1.48\cdot 10^{-5}N$

The electrostatic force exerted between the two sphere is given by:

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1, q2 are the charges on the two spheres

r is the separation between the centres of the two spheres

In this problem,

$q_1 = 12\cdot 10^{-9} C\\q_2 = -23\cdot 10^{-9} C\\r = 0.41 m$

Substituting these values into the equation, we find the force

$F=(9\cdot 10^9 Nm^2 C^{-2} )\frac{(12\cdot 10^{-9}C)(-23\cdot 10^{-9} C)}{(0.41 m)^2}=-1.48\cdot 10^{-5}N$

And the negative sign means the force is attractive, since the two spheres have charges of opposite sign.

(b) $+1.62\cdot 10^{-6}N$

The total net charge over the two sphere is:

$Q=q_1 +q_2 = 12\cdot 10^{-9}C+(-23\cdot 10^{-9}C)=-11\cdot 10^{-9} C$

When the two spheres are connected, the charge distribute equally over the two spheres (since they are identical, they have same capacitance), so each sphere will have a charge of

$q=\frac{Q}{2}=\frac{-11\cdot 10^{-9}C}{2}=-5.5\cdot 10^{-9}C$

So the electrostatic force between the two spheres will now be

$F=k\frac{q^2}{r^2}$

And substituting numbers, we find

$F=(9\cdot 10^9 Nm^2 C^{-2} )\frac{(-5.5\cdot 10^{-9} C)^2}{(0.41 m)^2}=+1.62\cdot 10^{-6}N$

and the positive sign means the force is repulsive, since the two spheres have same sign charges.

7 0

3 years ago

Suppose we have a load in which the voltage is v (t )space equals space 15 space cos (200 pi t plus 65 degree ). Furthermore, th

enot [183]

Answer:

IV. j1.06, capacitive

Explanation:

V(t) = 15cos( 200πt + 65 )

Irms = 10 A .

current leads by 90 degree.

reactance of the load .

Imax = Irms x √2

= 10 x √2

= 14.14 A

Now, Imax = Vmax / reactance

reactance = Vmax / Imax

= 15 / 14.14

= 1.06 ohm

Since current leads the voltage therefore , it must contain capacitance .

the load is capacitative. .

6 0

3 years ago

Read 2 more answers

A uniform disk with radius R = 0.400 m and mass 30.0 kg rotates in a horizontal plane on a frictionless vertical axle that passe

Rom4ik [11]

Answer:

The angle of rotation given is incorrect, the correct function to have a balanced unit is

θ(t) = (1.10 rad/s)t + (6.30 rad/s²)t²

Explanation:

Given that,

Radius of disk is

R = 0.4m

Mass of disk

M = 30kg

The angle of rotation is a function of time and it is given as

θ(t) = (1.10 rad/s)t + (6.30 rad/s²)t²

What is linear angular acceleration "a" when it rotates 0.1rev

θ = 0.1 rev

1 rev = 2πrad

θ = 0.1 × 2πrad = 0.63 rad

Let calculate the time it revolves 0.63rad

θ(t) = (1.10 rad/s)t + (6.30 rad/s²)t².

0.63 = 1.1t + 6.3t²

6.3t² + 1.1t - 0.63 = 0

Solving this quadratic equation using formula method

t = [-b±√(b²-4ac)]/2a

a = 6.3 b = 1.1 c = -0.63

t = [-1.1 ± √(1.1²-4×6.3×-0.63)]/2×6.3

t = -1.1±√(1.21+15.876) / 12.6

t = -1.1 ± 4.13 / 12.6

Let discard the negative time

So, t = (-1.1 + 4.13) / 12.6

t = 0.24 s

Now,

Angular velocity can be determine using

ωz = dθ / dt

ωz = 1.1 + 12.6t, since t = 0.24

ωz = 1.1 + 12.6(0.24)

ωz = 4.124 rad/s

Angular acceleration can be determine using

αz = dωz/dt

αz = 12.6 rad/s²

The radial acceleration can be determined using

ar = ωz²•R

ar = 4.124² × 0.4

ar = 6.8 m/s²

Also, the tangential Acceleration is related to angular acceleration using

at = αz • R

at = 12.6 × 0.4

at = 5.04 m/s²

Then, the magnitude of the resultant acceleration can be calculated using

a = √(ar² + at²)

a = √(6.8² + 5.04²)

a = √71.64

a = 8.46 m/s²

Direction

β = Arctan(at/ar)

β = Arctan(5.04/6.8)

β = 36.54

This is the direction from the origin

But it has already revolve 0.1rev

1 rev = 360°

Then, θ = 0.1° = 360 × 0.1 = 36°

Direction = β — θ

Then, it direction is 36.54 — 54° = 0.54°

The direction is 0.54°

Check attachment for direction understanding

4 0

3 years ago

Do black holes really exist?

mel-nik [20]

Yes, black holes 100% exist. They suck everything in their paths through a process known as spaghettification.

5 0

3 years ago

60 kilometers in 4 hours, what is the average speed?​

60 kilometers in 4 hours, what is the average speed?