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Fantom [35]
3 years ago
9

60 kilometers in 4 hours, what is the average speed?​

Physics
1 answer:
allsm [11]3 years ago
8 0

Average speed = (distance covered) / (time to cover the distance)

Average speed = (60 kilometers) / (4 hours)

Average speed = (60/4) kilometer/hour

<em>Average speed = 15 km/hr</em>

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A relief plane flying horizontally at 65.0 m/s is delivering a
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The height of the plane delivering a food package to people stranded on an island is 722.2 m.

<h3>Time of motion of the food package</h3>

The time taken for the food package to hit the ground level is calculated as follows;

X = vt

where;

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t = X/v

t = 789/65

t = 12.14 seconds

<h3>Height of the plane</h3>

h = ¹/₂gt²

where;

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h = (0.5)(9.8)(12.14²)

h = 722.2 m

Thus, the height of the plane delivering a food package to people stranded on an island is 722.2 m.

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How to indicate kinetic energy
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Ba-11 when passing through a lock, which light means "approach the lock under full control?"
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A0.350 kg iron horseshoe that is initially at 600°C is dropped into a bucket containing 21.9 kg of water at 21.8°C. What is the
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Answer: 22.8^0C

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Q_{absorbed}=Q_{released}

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Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]      

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m_1 = mass of iron horseshoe = 0.35 kg = 350 g (1kg=1000g[/tex]

m_2 = mass of water = 21.9 kg = 21900 g

T_{final} = final temperature = ?

T_1 = temperature of iron horseshoe = 600^oC

T_2 = temperature of water = 21.8^oC

c_1 = specific heat of iron horseshoe = 0.450J/g^0C

c_2 = specific heat of water =  4.184J/g^0C

Now put all the given values in equation (1), we get

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]

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Therefore, the final equilibrium temperature is 22.8^0C.

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