A 1500 kg aircraft going 35 m/s collides with a 2000 kg aircraft that is parked and they stick together after the collision and

Question

2 years ago

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A 1500 kg aircraft going 35 m/s collides with a 2000 kg aircraft that is parked and they stick together after the collision and

are going 15 m/s after the collision. If they skid for 112.1 m before stopping, how long (in seconds) did they skid? Hint: Are the aircraft moving at a constant velocity after the collision or do they experience an acceleration?

Physics

1 answer:

Elis [28] · Answer 1 · 2023-05-24T08:01:17+03:00

The two aircrafts are skidded for 14.9 s.

To find the answer, we need to know about the Newton's equation of motion.

<h3>What is the Newton's equation that relates velocity, distance, acceleration and time?</h3>

As per Newton's equation of motion

V²-U²= 2aS
V= U+at
V= final velocity, U = initial velocity, S = distance, a= acceleration, t= time

<h3>What's the acceleration of the aircrafts that skidded from 35 m/s after the collision for 112.1 m before achieving 15 m/s?</h3>

Here, U = 35 m/s, V = 15m/s, S= 112.1 m
So, 15²- 35²= 2a×112.1= 224.2a

=> a= -1000/224.2= -4.5 m/s²

<h3>What's the time taken to stop if these aircrafts are de-accelerated by 4.5 m/s² from 35m/s?</h3>

Here, U = 35 m/s, V=15 m/s a= -4.5 m/s²
35= 15+(-4.5)t

=> t= 20/4.5 = 4.4 s

Thus, we can conclude that the two aircrafts are skidded for 4.4 s.

Learn more about the Newton's equation of motion here:

brainly.com/question/25545050

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