When
, we have


and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)
Suppose this is true for
, that

Now for
, we have

so we know the left side is at least divisible by
by our assumption.
It remains to show that

which is easily done with Fermat's little theorem. It says

where
is prime and
is any integer. Then for any positive integer
,

Furthermore,

which goes all the way down to

So, we find that

QED
Answer:
The length of the rectangle is;
5x(x+13)/(x-5)
Step-by-step explanation:
Mathematically, we know that the area of a rectangle is the product of the length and width of the triangle
To find the length of the rectangle, we will have to divide the area by the width
we have this as;
(x^2 + 15x + 26)/6x^2 divided by (x^2-3x-10)/30x^3
thus, we have ;
(x^2 + 15x + 26)/6x^2 * 30x^3/(x^2-3x-10)
= (x^2+15x+ 26)/(x^2-3x-10) * 5x
But;
(x^2 + 15x + 26) = (x+ 2)(x+ 13)
(x^2-3x-10) = (x+2)(x-5)
Substituting the linear products in place of the trinomials, we have;
(x+2)(x+13)/(x+2)(x-5) * 5x
= 5x(x+13)/(x-5)
Step-by-step explanation:
7. ∆ABC = ∆ILH by SSS
as, AB = IL , BC = LH , CA = HI
8. ∆DEF = ∆AMS by ASA
as , angle D = angle A, EF = MS , angle F = Angle S
9. ∆JKL = ∆HAT by SAS
as, JK = HA , KL = AT , angle L = angle T
10. ∆ABC = ∆KPG by ASA
as , CA = GK, Angle c = angle G and Angle B = angle P
11. ∆ABC = ∆YDE by ASA
as , angle A = angle Y, AB = YD , angle B = angle D
12. ∆MNO = ∆SAK by ASA
as , Angle M = angle S, NO = AK, angle O = angle K
<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>and </u></em><em><u>may </u></em><em><u>u</u></em><em><u> have</u></em><em><u> a</u></em><em><u> great</u></em><em><u> day</u></em><em><u> ahead</u></em><em><u>!</u></em>
Answer:
5,000+5,000= 10000
Step-by-step explanation:
4/3 is greater than 4/8
This is because 4/3 is 1.33 in decimal from. Whereas 4/8 is 1/2 in decimal form
So, obviously 4/3 is greater ;)