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2 years ago

Find the product of 2.7 and 3.59.

Mathematics

1 answer:

Paha777 [63]2 years ago

3 0

Answer:

9.693 hope this helps!!!

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Find the area of the triangle.

Ne4ueva [31]

Answer:

10.92cm

Step-by-step explanation:

We can solve this problem by taking the formula to the area of a triangle and substituting our given numbers with the variables in it.

$A = \frac{1}{2}bh$ , where $b$ represents base and $h$ represents height.

So, if we substitute our given measurements with the variables in this formula, we can easily solve this.

$A = \frac{1}{2}(2.8)(7.8)$

Then, using the order of operations, we multiply and ultimately solve this problem.

$\frac{1}{2}*2.8 = 1.4$

$1.4*7.8=10.92$

Thus, our answer is 10.92cm.

5 0

3 years ago

For what value of a does (1/9)^a+1 = 81^a+1 • 27^2-a

Fantom [35]

Answer: a = -4

Step-by-step explanation:

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3 years ago

The football team has a total of 50 jerseys. There are 5 medium-sized jerseys. What percent of the jerseys are medium-sized jer

laila [671]

The answer would be 10%

4 0

3 years ago

Read 2 more answers

What is the value of x?

Alexandra [31]

Answer:

The value of x=27

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe

WARRIOR [948]

Answer:

7536 $km^3/sec$

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

$Volume = \pi r^2h$

Where $r$ is the radius and

$h$ is the height of cylinder.

As per question statement:

$r$ = 40 km (variable)

$h$ = 2.5 (constant)

$\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h$

As $\pi, h$ are constant:

$\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec$

4 0

3 years ago