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katrin2010 [14]
2 years ago
8

One of these cars is black and the other is red (really). They are illuminated by sodium lamps which have dominantly yellow ligh

t. Why do the cars both appear to be dark in color
Physics
1 answer:
nekit [7.7K]2 years ago
8 0

The two cars illuminated by sodium lamps appear black because the red and black colours are absorbed and no colour is reflected.

<h3>What is reflection of light?</h3>

Reflection of light is the ability of light rays to bounce back off a surface when they are incident on that surface

The ability of light to be reflected gives rise to changes in the colour of objects

When light is incident on a surface, the colour that is reflected gives the colour of that object.

Therefore, when two cars of red and black colur are illuminated by sodium lamps, they appear black because the red and black colours are absorbed and no colour is reflected.

Learn more about reflection of light at: brainly.com/question/1191238

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A body-centered cubic lattice has a lattice constant of 4.83 Ă. A plane cutting the lattice has intercepts of 9.66 Å, 19.32 Å, a
anastassius [24]

Answer:

Miller Indices are [2, 4, 3]

Solution:

As per the question:

Lattice Constant, C = 4.83 \AA

Intercepts along the three axes:

\bar{x} = 9.66 \AA

\bar{x} = 19.32 \AA

\bar{x} = 14.49 \AA

Now,

Miller Indices gives the vector representation of the atomic plane orientation in the lattice and are found by taking the reciprocal of the intercepts.

Now, for the Miller Indices along the three axes:

a = \frac{1}{9.66}

b = \frac{1}{19.32}

c = \frac{1}{14.49}

To find the Miller indices, we divide a, b and c by reciprocal of lattice constant 'C' respectively:

a' = \frac{\frac{1}{9.66}}{\frac{1}{4.83}} = \frac{1}{2}

b' = \frac{\frac{1}{19.32}}{\frac{1}{4.83}} = \frac{1}{4}

c' = \frac{\frac{1}{14.49}}{\frac{1}{4.83}} = \frac{1}{3}

7 0
3 years ago
What measurement do geologists use to find absolute age
Alona [7]

Answer:

see below :)

Explanation:

Radiometric dating.

8 0
3 years ago
Read 2 more answers
Please help! I especially need help with the second question but help with the first one would be most appreciated!
lara31 [8.8K]

Answer:

a) Team A will win.

b) The losing team will accelerate towards the middle line with 0.01 m/s^{2}

Explanation:

Given that Team-A pulls with a force , F_{1} = 50N

and Team-B pulls with a force , F_{1} = 45N

∵ F_{1} > F_{2}

The rope will move in the direction of force F_{1}.

∴ Team-A will win.

b) Considering both the teams as one system of total mass , m = 246+253 = 499 kg

Net force on the system , F = F_{1} - F_{2} = 50-45 = 5N

Applying Newtons first law to the system ,

F = ma , where 'a' is the acceleration of the system.

Since , both the teams are connected by the same rope , their acceleration would be the same.

∴ 5 = 499×a

∴ a = 0.01 m/s^{2}

4 0
4 years ago
A supersonic airplane is flying horizontally at a speed of 2650 km/h. What is the centripetal acceleration of the airplane, if i
Andrew [12]

Answer:

a_{c}=82617.65km/h^{2}\\  or\\a_{c}=6.37m/s^{2}

Explanation:

Given data

Speed v=2650 km/h

Radius r=85.0 km

To find

Centripetal Acceleration

Solution

As centripetal acceleration is given as

a_{c}=\frac{v^{2} }{r}................eq(i)

where

v is velocity

r is the radius

Substitute the given values in eq(i)

a_{c}=\frac{(2650km/h)^{2} }{85km} \\a_{c}=82617.65km/h^{2}\\  or\\a_{c}=6.37m/s^{2}

5 0
4 years ago
If the Force exerted by the intern is doubled and the distance is halved, does the done by the intern increase, decrease, or rem
Jlenok [28]

Remain the same

Explanation:

If the force exerted by the intern is doubled and the distance is halved, the work done by the intern remains the same.

 Work done is the force applied to move a body through a distance.

Work done = F x d

where F is the applied force

            d is the distance moved

Now;

if:

    f = 2f

    d = \frac{1}{2}d

Input the parameter:

 Work done = fxd = 2f x \frac{1}{2}d  = fd

The work done will still remain the same

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

3 0
4 years ago
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