Question

A supersonic airplane is flying horizontally at a speed of 2650 km/h. What is the centripetal acceleration of the airplane, if it turns from North to East on a circular path with a radius of 85.0 km?

Answer 1

Answer:

$a_{c}=82617.65km/h^{2}\\ or\\a_{c}=6.37m/s^{2}$

Explanation:

Given data

Speed v=2650 km/h

Radius r=85.0 km

To find

Centripetal Acceleration

Solution

As centripetal acceleration is given as

$a_{c}=\frac{v^{2} }{r}................eq(i)$

where

v is velocity

r is the radius

Substitute the given values in eq(i)

$a_{c}=\frac{(2650km/h)^{2} }{85km} \\a_{c}=82617.65km/h^{2}\\ or\\a_{c}=6.37m/s^{2}$