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3 years ago

What measurement do geologists use to find absolute age

Physics

2 answers:

Alona [7]3 years ago

8 0

Answer:

see below :)

Explanation:

Radiometric dating.

Inga [223]3 years ago

8 0

Geologists use a variety of techniques to establish absolute age, including radiometric dating, tree rings, ice cores, and annual sedimentary deposits called varves.

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John’s mass is 95.6 kg, and Barbara’s is 55.3 kg. He is standing on the x axis at xJ = +10.9 m, while she is standing on the x a

Anna11 [10]

Answer:Shifted towards Left by distance of 2.243 m

Explanation:

Given

Mass of john $m_1=95.6 kg$

Mass of barbara $m_2=55.3 kg$

John is standing at $x=10.9 m$

Barbara is standing at $x=2.50 m$

$x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}$

$x_{com}=\frac{95.6\times 10.9+55.3\times 2.5}{95.6+55.3}$

$x_{com}=\frac{1180.29}{150.9}$

$x_{com}=7.821 m$

Now if they change their Position then

$x'_{com}=\frac{95.6\times 2.5+55.3\times 10.9}{95.6+55.3}$

$x'_{com}=\frac{841.77}{150.9}$

$x'_{com}=5.578$

Thus we can see that center of mass shifted towards left by a distance of $2.243 m$ because heavier is shifted towards left

8 0

3 years ago

A cyclist moves at a constant speed of 5 m/s if the cyclist does not accelerate during the next 20 seconds he will travel at?

Verizon [17]

5 m/s because the speed is constant

8 0

3 years ago

What average force is required to stop a 980 kg car in 9.0 s if the car is traveling at 91 km/h ?

kozerog [31]

Newton's second law of motion:
F=ma
$a = \frac{v}{t}$
You convert from km/h to m/s by dividing by 3.6:
$v = 91 \div 3.6$
$v = 25.3 \: \frac{m}{s}$
Then a is:
$a = \frac{25.3}{9}$
$a = 2.8 \frac{m}{s {}^{2} }$
Then:
F=(980)(2.8)=2744 N

5 0

3 years ago

A train pulls the boxcars. What are the vertical forces present? (1 point)

Greeley [361]

The vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.

The forces exerted on an object can be resolved into horizontal and vertical components.

The horizontal components of the forces on an object being pulled include the following;

The frictional force on the object; which tends to reduce the motion,

force dragging the object forward

if the object is inclined to an angle, the horizontal component of the weight

This horizontal force is written as;

$\Sigma F_x = 0\\\\F_x - F_k = ma$

The vertical component of the force on the object include the following;

the weight of the object acting downwards

the pull of air on the object acting upwards

The vertical force on the object is written as;

$\Sigma F_n = 0\\\\F_n - W = 0$

Thus, the vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.

Learn more here: brainly.com/question/2000189

5 0

3 years ago

Can someone help with these

yaroslaw [1]

One

Givens

delta B = 0.20 T/s
A = 0.07 m^2
R = 3.5 ohms

Formula

Φ = ΔB*A

e = Φ

Solution (first part)

e = 0.2 * 0.07

e = 0.014 emf

Solution (second part)

i = e/R

i = 0.014 / 3.5

i = 4 * 10^-3

i = 4 ma

Answer

Two

Givens

N = 200 turns

Φ = 30 degrees

Delta B = 0.45 T/s

phi = 30 degrees

r = 0.06 meters

Formula

e = -N * delta B * A * Cos(phi)

Solution

e = -200 * 0.45 (pi r^2) * Cos(30)

e = - 200 * 0.45 * (3.14 * 0.06^2) * cos(30)

e = 0.881 emf

Answer

4 0

3 years ago