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Zigmanuir [339]
3 years ago
6

Siobhan wants to measure the mass of a bag of flour. What should she use?

Physics
2 answers:
yan [13]3 years ago
4 0

Answer:

A weighing scale

Explanation:

A weighing scale graduated in grams or kilograms can be used.

ddd [48]3 years ago
3 0

This depends on how big the bag is. Most commonly, the bag weighs 2 kg to 10 kg or more. With this range of weight, Siobhan should use a balance to measure the mass of the flour and record the mass in kilograms. Thus, the answer is the first choice

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He does whatever a spider can. Spider-Man, who has a mass of 76 [kg], is clinging onto an inclined wall forming an inclination a
Aliun [14]

Answer:570.54 N

Explanation:

Given

mass of man=76 kg

\theta =50^{\circ}

As man is standing over inclined building therefore

its weight has two components i.e. sin and cos component

Force perpendicular to inclined wall

F=mgcos\theta =76\times 9.8\times \sin 50

F=570.54 N

4 0
3 years ago
What is the net force of a 25 g object with an acceleration of 3 m/s^2? 100PTS
gayaneshka [121]

Explanation:

Force=Mass×acceleration

force=25×3

force=75N

5 0
3 years ago
Read 2 more answers
A train starts at rest in a station and accelerates at a constant 0.987 m/s2 for 182 seconds. Then the train decelerates at a co
algol [13]

Answer:

\displaystyle X_T=66.6\ km

Explanation:

<u>Accelerated Motion </u>

When a body changes its speed at a constant rate, i.e. same changes take same times, then it has a constant acceleration. The acceleration can be positive or negative. In the first case, the speed increases, and in the second time, the speed lowers until it eventually stops. The equation for the speed vf at any time t is given by

\displaystyle V_f=V_o+a\ t

where a is the acceleration, and vo is the initial speed .

The train has two different types of motion. It first starts from rest and has a constant acceleration of 0.987 m/s^2 for 182 seconds. Then it brakes with a constant acceleration of -0.321 m/s^2 until it comes to a stop. We need to find the total distance traveled.

The equation for the distance is

\displaystyle X=V_o\ t+\frac{a\ t^2}{2}

Our data is

\displaystyle V_o=0,a=0.987m/s^2,\ t=182\ sec

Let's compute the first distance X1

\displaystyle X_1=0+\frac{0.987\times 182^2}{2}

\displaystyle X_1=16,346.7\ m

Now, we find the speed at the end of the first period of time

\displaystyle V_{f1}=0+0.987\times 182

\displaystyle V_{f1}=179.6\ m/s

That is the speed the train is at the moment it starts to brake. We need to compute the time needed to stop the train, that is, to make vf=0

\displaystyle V_o=179.6,a=-0.321\ m/s^2\ ,V_f=0

\displaystyle t=\frac{v_f-v_o}{a}=\frac{0-179.6}{-0.321}

\displaystyle t=559.5\ sec

Computing the second distance

\displaystyle X_2=179.6\times559.5\ \frac{-0.321\times 559.5^2}{2}

\displaystyle X_2=50,243.2\ m

The total distance is

\displaystyle X_t=x_1+x_2=16,346.7+50,243.2

\displaystyle X_t=66,589.9\ m

\displaystyle \boxed{X_T=66.6\ km}

8 0
4 years ago
Which of these has the least chemical energy?
madreJ [45]

The answer is option D a gallon of gasoline.

Explanation:

A gallon of gasoline has the least chemical energy. The energy content of gallon of gasoline is about 132,000 Btu. The gasoline produced is equivalent in energy terms to 4 kilowatt hours.

Gasoline has chemical potential energy stored in chemical bonds. Gasoline is called as gas or petrol, mixture of volatile, flammable liquid hydrocarbons are used as fuel for internal- combustion engines. It is used as solvent for oils and fats.

Gasoline gallon equivalent is the alternative fuel taken to equal the energy content of one liquid gallon of gasoline.

4 0
3 years ago
The surface of the Sun has a temperature of about 5 800 K. If the radius of the Sun is 7 × 108 m, determine the power output of
Nimfa-mama [501]

Answer:

a. 3.95\times10^{26}W

Explanation:

T = temperature of the surface of sun = 5800 K

r = Radius of the Sun = 7 x 10⁸ m

A = Surface area of the Sun

Surface area of the sun is given as

A = 4\pi r^{2} \\A = 4(3.14) (7\times10^{8})^{2}\\A = 6.2\times10^{18} m^{2}

e = Emissivity = 1

\sigma = Stefan's constant = 5.67 x 10⁻⁸ Wm⁻²K⁻⁴

Using Stefan's law, Power output of the sun is given as

P = \sigma e AT^{4} \\P = (5.67\times10^{-8}) (1) (6.2\times10^{18}) (5800)^{4}\\P = 3.95\times10^{26} W

4 0
4 years ago
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