Answer:
α = τ/I = 0.77 / (0.70(0.30²)) = 12.22222... = 12 rad/s²
Explanation:
Assume the snow is uniform, and horizontal.
Given:
coefficient of kinetic friction = 0.10 = muK
weight of sled = 48 N
weight of rider = 660 N
normal force on of sled with rider = 48+660 N = 708 N = N
Force required to maintain a uniform speed
= coefficient of kinetic friction * normal force
= muK * N
= 0.10 * 708 N
=70.8 N
Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.
you can collect water and shine a light though it and record your finings
Answer:
6 second
Explanation:
initial velocity of ball, u = 60 m/s
g = 10 m/s^2
Let the ball takes time t to reach at the maximum height
We know that at maximum height, the velocity of ball is zero.
v = 0 m/s
Use first equation of motion
v = u + gt
0 = 60 - 10 x t
t = 6 second
Thus, the ball takes 6 second to reach to maximum height.