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3 years ago

Help pls!!!! Do questions 2-5 I will give branlist point!

Mathematics

2 answers:

masya89 [10]3 years ago

7 0

What do you need help with? Please give me a photo or something so that I can help you with it. All I see is “Please help me, this is due at midnight!!” Next time please give US a picture or something so I can be able to help you, Thank you, Sincerely Unknown.

tresset_1 [31]3 years ago

7 0

Restate the question and then put numbers

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What is the length of the hypotenuse of a right triangle with leg lengths of 8 inches and 15 inches?

pentagon [3]

The answer is c 21...

8 0

4 years ago

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On his first day of school, Kareem found the high temperature in degrees Fahrenheit to be 76.1°. He plans to use the function to

blsea [12.9K]

The correct option is THE TEMPERATURE OF 76.1 DEGREES FAHRENHEIT CONVERTED TO DEGREE CELSIUS.
The symbol C stands for degree Celsius and is always attached to every temperature measurement that is done using the Celsius measure.

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3 years ago

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Find all solutions in the interval [0, 2π). <br> 2 sin2x = sin x

tester [92]

Answer:

The solutions on the given interval are :

$0$

$\pi$

$\cos^{-1}(\frac{1}{4})$

$-\cos^{-1}(\frac{1}{4})+2\pi$

Step-by-step explanation:

We will need the double angle identity $\sin(2x)=2\sin(x)\cos(x)$ .

Let's begin:

$2\sin(2x)=\sin(x)$

Use double angle identity mentioned on left hand side:

$2\cdot 2\sin(x)\cos(x)=\sin(x)$

Simplify a little bit on left side:

$4\sin(x)\cos(x)=\sin(x)$

Subtract $\sin(x)$ on both sides:

$4\sin(x)\cos(x)-\sin(x)=0$

Factor left hand side:

$\sin(x)[4\cos(x)-1]=0$

Set both factors equal to 0 because at least of them has to be 0 in order for the equation to be true:

$\sin(x)=0 \text{ or } 4\cos(x)-1=0$

The first is easy what angles $\theta$ are $y$ -coordinates on the unit circle 0. That happens at $0$ and $\pi$ on the given range of $x$ (this $x$ is not be confused with the $x$ -coordinate).

Now let's look at the second equation:

$4\cos(x)-1=0$

Isolate $\cos(x)$ .

Add 1 on both sides:

$4 \cos(x)=1$

Divide both sides by 4:

$\cos(x)=\frac{1}{4}$

This is not as easy as finding on the unit circle.

We know $\arccos( )$ will render us a value between $0$ and $2\pi$ .

So one solution on the given interval for x is $x=\cos^{-1}(\frac{1}{4})$ .

We know cosine function is even.

So an equivalent equation is:

$\cos(-x)=\frac{1}{4}$

Apply $\cos^{-1}$ to both sides:

$-x=\cos^{-1}(\frac{1}{4})$

Multiply both sides by -1:

$x=-\cos^{-1}(\frac{1}{4})$

This going to be negative in the 4th quadrant but if we wrap around the unit circle, $2\pi$ , we will get an answer between $0$ and $2\pi$ .

So the solutions on the given interval are :

$0$

$\pi$

$\cos^{-1}(\frac{1}{4})$

$-\cos^{-1}(\frac{1}{4})+2\pi$

5 0

3 years ago

Work out (5x10^3) x (5x10^7) standard form

dmitriy555 [2]

5*10^3 * 5*10^7= 5*5 *10^3*10^7=25*10^10

Generally u are allowed to leave it as it is but if no

25*10^10=25 * 10000000000 = 250000000000

Here u are!

3 0

3 years ago

An online video game club charges $10 to join and $8 per month after that. Which equation can you solve to find out how long you

Arlecino [84]

You have to add 10 last.
divide 75÷8 and then add 10
$(75 \div 8) + 10$

4 0

3 years ago