4x3+2 = 14/3 —> 56/12
1x4+3 = 7/4 —> 21/12
56-21 is equal to 35/12
Which is 2 and 11/12
By using trigonometric relations, we will find that:
sin(θ) = (√33)/7 = √(33/49)
<h3>How to find the value of the sine?</h3>
Remember that for a right triangle, we have the relations:
cos(a) = (adjacent cathetus)/(hypotenuse)
sin(a) = (opposite cathetus)/(hypotenuse).
Here we know that:
cos(θ) = 4/7
Then we can say that we have a triangle with an adjacent cathetus of 4 units and a hypotenuse of 7 units. Now we need to find the other cathetus.
opposite cathetus = √(7^2 - 4^2) = √33
Then we can write:
sin(θ) = (√33)/7 = √(33/49)
If you want to learn more about trigonometry.
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Answer:among us
Step-by-step explanation:
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Jack would have twenty craft sticks because four times that number is the same as x4 so you would do 5x4=20.
The answer is: " 2 :5 " ; or, write as: " 2/5 " .
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The ratio of 'girls' to 'all students' is: "2: 5 " ; or, write as: " 2/5 ".
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Explanation:
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Given: The ratio of boys to girls is: " 3:2 " .
Problem: Find the ratio of "girls" to "all students:
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Note: This ratio of "boys to girls", which is " 3 : 2 " ;
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→ can be expressed as " 3x: 2x" ;
in which the total number of students is: " 3x + 2x " = 5x " .
→ The total number of students is represented as: " 5x " .
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→ The ratio of "girls to boys" is: "2x : 3x" .
→ {that is; the "inverse" of the ratio of "boys to girls"} ;
→ {that is; the "inverse" of " 3x: 2x" } ; → which is: " 2x : 3x " .
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The ratio of "girls" to "all students" is: "2x : 5x " ; or " 2x/5x " ;
→ Both "x" values cancel ; {since: " x/x = 1 "} ;
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→ and we have the answer: " 2 :5 " ; or, write as: " 2/5 " .
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The ratio of 'girls' to 'all students' is: " 2 :5 " ; or, write as: " 2/5 ".
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