Answer:- 23.0 mg
Solution:- Radioactive decay obeys first order kinetics and the first order kinetics equation is:
where, 
is the initial amount of radioactive substance and N is it's amount after time t. k is the decay constant.
From given information, Original amount, of the radioactive substance is 184 mg and we are asked to calculate the amount N after 15 days. It means, t = 15 days
Half life is given as 5 days. From the half life, we could calculate the decay constant k using the equation:
where, 
is the symbol for half life. let's plug in the value of half like to calculate k:
Let's plug in the values in the first order kinetics equation and solve it for N:
lnN = 3.136
N = 23.0 mg
So, 23.0 mg of Bi-210 would be remaining after 15 days.
Nuclear Fusion.
Having low atomic nuclei is the reason why uranium-235 is not commonly found in large nuclear reactions.
So, scientist increases its concentration by fusing the lower atomic nuclei with high atomic nuclei in order to produce a heavier nucleus which will increase the release of energy.
elements using your lessons and experience within this virtual lab. 150 words max its a
Answer:
1 mol of electron is exchanged. The mol of electrons that is released by the iron, is gained by the silver.
Explanation:
We need to determine the half reactions:
Ag⁺ → Ag
These is the reduction reaction, where Silver decreases the oxidation state. It gained 1 mol of e⁻
Fe²⁺ → Fe³⁺
In this case, iron increases the oxidation state, from +2 to +3. It has released 1 mol of electrons. This is the oxidation reaction.
The complete redox is:
Ag⁺ + 1e⁻ → Ag
Fe²⁺ → Fe³⁺ + 1e⁻
Ag⁺(aq) + 1e⁻ + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq) + 1e⁻
The electrons will be cancelled.
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