Carbonated drinks have the air under pressure so that carbon bubbles are forced into the drink, keeping it carbonated. So when you open a can, the air under pressure in the can comes out of the can at a high speed, making a "whooshing" sound. The gas law that applies to this concept is the Boyle's Law (PV=k or P1V1=P2V2).
Answer:
If NaOH of a known concentration neutralizes HCl of an unknown concentration, then you can use the volumes to determine the concentration of the HCl, because, at the equilibrium point, the number of moles of HCl equals the number of moles of NaOH.
Explanation:
I just finished the assignment.
10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl
Explanation:
Step 1: To make Si equal on both sides. put 10 in front of HSiCl3
10 HSiCl3+ H2O →H10Si10O15+ HCl
Step 2: By putting 30 in front of HCl, Cl can be balanced
10 HSiCl3+ H2O →H10Si10O15+ 30 HCl
Step 3: Now, balance O by putting 15 in front of H2O
10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl
Hence the balanced equation is:
10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl
Colligative properties calculations are used for this type of problem. Calculations are as follows:
ΔT(boiling point) = 101.02 °C - 100.0 °C= 1.02 °C
<span>ΔT(boiling point) = (Kb)m
</span>m = 1.02 °C / 0.512 °C kg / mol
<span>m = 1.99 mol / kg
</span><span>ΔT(freezing point) = (Kf)m
</span>ΔT(freezing point) = 1.86 °C kg / mol (<span>1.99 mol / kg)
</span>ΔT(freezing point) = 3.70 <span>°C
</span>Tf - T = 3.70 <span>°C
T = -3.70 </span><span>°C</span>
Answer:
A condensate is a liquid formed by condensation.
Explanation:
