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3241004551 [841]
3 years ago
10

Because uranium-235 isn't found naturally in large quantities, engineers increase its concentration in nuclear fuel so that a ch

ain reaction is more likely to occur. what is the name of this process?
Chemistry
2 answers:
likoan [24]3 years ago
8 0

Answer:

A. enrichment (apex)

Vitek1552 [10]3 years ago
3 0
Nuclear Fusion. 

Having low atomic nuclei is the reason why uranium-235 is not commonly found in large nuclear reactions. 

So, scientist increases its concentration by fusing the lower atomic nuclei with high atomic nuclei in order to produce a heavier nucleus which will increase the release of energy. 
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What is an electron and proton?
kirza4 [7]

Explanation:

An electron is a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

A proton is a stable subatomic particle occurring in all atomic nuclei, with a positive electric charge equal in magnitude to that of an electron, but of opposite sign.

6 0
4 years ago
An egg foam used in angel food cake is an example of which type of colloidal
Sergio [31]

Answer:

In food systems, the continuous phase is usually a liquid with added solids or  beaten egg white and sugar foam is a gas in the liquid dispersion. ... egg white foam is an example of this. air bubbles (disperse phase are ... a colloid is a type of chemical mixture where one substance is dispersed evenly throughout.

Explanation:

7 0
3 years ago
Which represents a linear graph?
Tpy6a [65]
Your answer is D. Hope this helps.
Linear graphs have representation as a STRAIGHT LINES.
7 0
3 years ago
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Xenon (xe) of mass 5.08 g reacts with fluorine to form 9.49 g of a xenon fluoride compound. what is the empirical formula of thi
jenyasd209 [6]
We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.

  mass of Xenon (Xe) = 5.08 g
  mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g

Determine the number of moles of each of the element in the compound. 
    moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
   moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F

The empirical formula is therefore,
      Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
<em>     XeF₆</em>
8 0
3 years ago
What happens when a low mass star runs out of fuel
kiruha [24]
I am not for sure, but i think it explodes :)
3 0
3 years ago
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