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Oksana_A [137]
2 years ago
15

Given that (x + 2) is a linear factor of the polynomial x3 + 4x2 + x – 6, what are the other two linear factors?A. (x – 1) and (

x + 3)B. (x + 1) and (x – 3)C. (x – 1) and (x – 3)D. (x + 1) and (x + 3)
Mathematics
1 answer:
kkurt [141]2 years ago
5 0

The other two linear factors of the polynomial x³ + 4x² +x -6 are; Choice A: (x – 1) and (x + 3)

<h3>Polynomial division</h3>

By ling division of polynomials, it follows that the division of polynomial x³ + 4x² +x -6 by x +2 yields the quadratic expression;

  • x² + 2x -3.

On this note, the factorisation of the quadratic expression above yields factors;

  • (x – 1) and (x + 3)

Read more on factorisation of polynomials;

brainly.com/question/280849

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The LCM of two number is a multiple of 10 and 6. The two numbers are both less then 10.what is the LCM?
SCORPION-xisa [38]
This question doesn't make sense since the LCM of 10 and 6 is 30.

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4 0
3 years ago
First six shipments:
tester [92]
For problems like this, we need to find the pattern between the set of numbers to create a general equation for f(x). Given that x is the shipment number, let us first observe the first six shipments' behavior.
1  10 |
2  16 = 10 + 1(6) |
3  22 = 10 + 2(6) |
4  28 = 10 + 3(6)|  
5  34 = 10 + 4(6) |
6  40 = 10 + 5(6) |

From these, we can observe that given x number of shipments, the total number of objects would be 10 + (x-1)6 = 10 + 6x - 6 = 6x +4. Thus, given f(x), we have 

f(x) = 6x + 4
Answer: f(x) = 6x + 4

3 0
3 years ago
Please help me !! pls pls pls
frutty [35]

Answer:

aas congruence postulate

6 0
2 years ago
Evaluate cos(sin^-1(4/5)
PSYCHO15rus [73]

Step-by-step explanation:

Let \:   \: \theta =  \sin^{ - 1}  (\frac{4}{5})  \\  \\  \therefore \:  \sin\theta = \frac{4}{5} \\  \\  \because \:  { \cos}^{2} \theta =1  - { \sin}^{2} \theta  \\  \\  \therefore \: { \cos}^{2} \theta  = 1 - (\frac{4}{5} )^{2}  \\ \\   = 1 -  \frac{16}{25}  \\  \\  =  \frac{25 - 16}{25}  \\  \\  =  \frac{9}{25}  \\  \\   \therefore \:{ \cos}\theta  = \pm \:  \frac{3}{5}  \\  \\  \because \:  \theta \: lie \: in \: the \: first \: quadrant \\  \\  \therefore \: { \cos}\theta  =  \:  \frac{3}{5}  \\ \\  \implies \theta =  { \cos}^{ -1 }  \: \frac{3}{5}\\\\\implies \theta =  { \cos}^{ -1 }  \: \frac{3}{5}= { \sin}^{ -1 }  \: \frac{4}{5} \\  \\  \therefore \:  \cos( \ {sin}^{ - 1}  \frac{4}{5} ) \\ \\ =  \cos( \ {cos}^{ - 1}  \frac{3}{5} )   \\\\ = \frac{3}{5}  \\  \\   \purple{ \boxed{\therefore \: \cos( \ {sin}^{ - 1}  \frac{4}{5} ) = \frac{3}{5}}}

8 0
3 years ago
How do I do this ???
Triss [41]

Answer:

He can cut 6 sections this length.

Step-by-step explanation:

he has

7(12) = 84 inches of rope.

84-34.5 = 49.5

49.5/8.25 = 6

4 0
3 years ago
Read 2 more answers
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