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kotegsom [21]
2 years ago
8

A guy wire for a suspension bridge runs from the ground diagonally to the top of the closest pylon to make a triangle. We can us

e the Pythagorean Theorem to find the length of guy wire needed. The square of the distance between the wire on the ground and the pylon on the ground is 528,000 feet. The square of the height of the pylon is 19,600 feet. So the length of the guy wire can be found by evaluating sqrt(528,000 + 19,600) . What is the length of the guy wire?​
Mathematics
1 answer:
forsale [732]2 years ago
6 0

Answer:

740

Step-by-step explanation:

{hyp}^{2}  = {opp}^{2}  +  {adj }^{2}

Opp=528, 000 feet

Adj = 19,600feet

Hyp=?

{x}^{2}  = 528000 + 19600

{x}^{2}  = 547600

x =  \sqrt{547600}

Therefore,

x = 740

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Where does a hole occur in the graph of y = x(x+2) / x(x-3)
Morgarella [4.7K]

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A

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Given

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7 0
3 years ago
A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and
gayaneshka [121]

Answer:

(832.156, \ 847.844)

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, \overline x = 840

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

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So, 98% CI is

$(\overline x - E, \overline x + E)$

(840-7.844 ,  \ 840+7.844)

(832.156, \ 847.844)

4 0
2 years ago
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