Hg(No3)2 +NaSO4 --->2NaNO3 + HgSO4(s)
calculate the moles of each reactant
moles=mass/molar mass
moles of Hg(NO3)2= 51.429g/ 324.6 g/mol(molar mass of Hg(NO3)2)=0.158 moles
moles Na2SO4 16.642g/142g/mol= 0.117 moles of Na2SO4
Na2SO4 is the limiting reagent in the equation and by use mole ratio Na2So4 to HgSO4 is 1:1 therefore the moles of HgSO4 =0.117 moles
mass of HgSO4=moles x molar mass of HgSo4= 0.117 g x 303.6g/mol= 35.5212 grams
Explanation:
Let there be 1 mole of CoCl2.
Mass of CoCl2 = 1mol * (129.839g/mol) = 129.839g
Mass of H2O = 309.99g - 129.839g = 180.151g
Moles of H2O = 180.151g / (18g/mol) = 10mol
Hence the mole ratio of CoCl2 to H2O is 1 : 10.
C i think i got this off of usa test prep in class
I think the answer is C respiratory system