All categories

3 years ago

Which base is the strongest?

Chemistry

2 answers:

slamgirl [31]3 years ago

7 0

Answer:

The strong base is with $H^+$ concentration equals to $1 \times 10^{-12} M$ .

Explanation:

The pH of the solution is defined as negative logarithm of $H^+$ ions in a solution.Higher the $H^+$ ions concentration lower will be the value of pH and more acidic will be the solution.

$pH=-\log[H^+]$

1) $[H+] = 1 \times 10^{-9} M$

$pH=-\log[1 \times 10^{-9} M]=9$ Most acidic solution

2) $[H+] = 1 \times 10^{-11} M$

$pH=-\log[1 \times 10^{11} M]=11$

3) $[H+] = 1 \times 10^{-10} M$

$pH=-\log[1 \times 10^{-10} M]=10$

4) $[H+] = 1 \times 10^{-12} M$

$pH=-\log[1 \times 10^{-12} M]=12$ Most basic solution

Over [174]3 years ago

4 0

Im assuming that 10-9, 10-10... is 10 to the power of 9 and 10 to the power of 10, respectively.

In the pH scale, acids are pH<7 and bases have pH>7. Each increase in pH makes something less acidic (or more basic) by 10.
Therefore [H+]=1x10^12 is the most basic

You might be interested in

In thermodynamics, we determine the spontaneity of a reaction by the sign of ΔG. In electrochemistry, spontaneity is determined

faltersainse [42]

Answer:

For A: The standard cell potential of the reaction is 4.4 V

For B: The standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C: The reaction is spontaneous as written.

Explanation:

For A:

The given chemical reaction follows:

$2Li(s)+Cl_2(g)\rightarrow 2Li^+(aq.)+2Cl^-(aq.)$

The given half reaction follows:

Oxidation half reaction: $Li(s)\rightarrow Li^+(aq.)+e^-;E^o_{Li^+/Li}=-3.04V$ ( × 2)

Reduction half reaction: $Cl_2(g)+2e^-\rightarrow 2Cl^-(aq.);E^o_{Cl_2/2Cl^-}=+1.36V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

Here, chlorine will undergo reduction reaction will get reduced.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=1.36-(-3.04)=4.4V$

Hence, the standard cell potential of the reaction is 4.4 V

For B:

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

n = number of electrons transferred = $2mol\text{ e}^-$

F = Faradays constant = $96500J/V.mol\text{ e}^-$

$E^o_{cell}$ = standard cell potential = 4.4 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 4.4=-849200J=-8.50\times 10^5J$

Hence, the standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C:

For a reaction to be spontaneous, the standard Gibbs free energy change of the reaction must be negative.

From above, the standard Gibbs free energy change of the reaction is coming out to be negative.

Hence, the reaction is spontaneous as written.

7 0

3 years ago

Magnesium burns with a very bright light. When the flame goes out, a White powder is left behind. what is the word equation for

melisa1 [442]

When magnesium is burned, it reacts with oxygen in air not with the fire. The fire is the energy needed for the reaction to happen. Magnesium reacts with oxygen forming magnesium oxide. The light emitted from the reaction is because the reaction produced a lot of heat.

6 0

3 years ago

The quantity, q grams, of the radioactive isotope strontium-90 present in a sample decreases by half over a period of about t =

velikii [3]

Notice q=3/2, is half of the original q = 3(1/2)t/28.8
your welcome

8 0

2 years ago

Read 2 more answers

What chemical change is magnetizing steel

labwork [276]

Magnetizing steel is a physical change, not a chemical change.

4 0