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serious [3.7K]
3 years ago
7

For which of the following will the entropy of the system increase?

Chemistry
1 answer:
snow_lady [41]3 years ago
3 0

Answer :  The correct option is, (d) sublimation of dry ice.

Explanation :

Entropy : It is defined as the measurement of randomness or disorderedness in a system.

The order of entropy will be,

As we are moving from solid state to liquid state to gaseous state, the entropy will be increases due to the increase in the disorderedness.

As we are moving from gaseous state to liquid state to solid state, the entropy will be decreases due to the decrease in the disorderedness.

(a) Condensation of steam.

Condensation : It is a type of process in which the phase changes from gaseous state to liquid state at constant temperature.

In this process, phase changes from gaseous state to liquid state that means the degree of disorderedness decreases. So, the entropy will also decreases.

(b) Reaction of magnesium with oxygen to form magnesium oxide.

Mg(s)+O_2(g)\rightarrow MgO(s)

In this reaction, the randomness of reactant molecules are more (solid+gas) and as we move towards the formation of product the randomness become less (solid) that means the degree of disorderedness decreases. So, the entropy will also decreases.

(d) Reaction of nitrogen and hydrogen to form ammonia.

N_2(g)+H_2(g)\rightarrow NH_3(g)

In this reaction, the randomness of reactant molecules are more (2 moles of gas) and as we move towards the formation of product the randomness become less (1 mole of gas) that means the degree of disorderedness decreases. So, the entropy will also decreases.

(d) Sublimation of dry ice.

Sublimation : It is a type of process in which the phase changes from solid state to gaseous state without passing through the liquid state at constant temperature.

In this process, phase changes from solid state to gaseous state that means the degree of disorderedness increases. So, the entropy will also increases.

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Answer:

CaF2 + CO3- ----> CaCO3 + 2 F-

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Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and
rusak2 [61]

Answer:

4Zn_(_s_)~+~7OH^-~_(_a_q_)~+~NO_3^-_(_a_q_)~+~6H_2O_(_l_)~-->4Zn(OH)_4^-^2_(_a_q_)~+~NH_3_(_g_)

-) Oxidizing agent: NO_3^-_(_a_q_)

-) Reducing agent: Zn_(_s_)

Explanation:

The first step is separate the reaction into the <u>semireactions</u>:

A.Zn~->Zn(OH)_4^-^2

B.NO_3^-~->~NH_3

If we want to balance in <u>basic medium </u>we have to follow the rules:

1. We adjust the oxygen with OH^-

2. We adjust the H with H_2O

3. We adjust the charge with e^-

Lets balance the first semireaction A. :

Zn~+~4OH^-~->Zn(OH)_4^-^2~+~2e^-

Now, lets balance semireaction B:

NO_3^-~+~8e^-~+~6H_2O~->~NH_3~+~9OH^-

Finally, we have to add the two semireactions:

_________________________________________

8~(Zn~+~4OH^-~->Zn(OH)_4^-^2~+~2e^-)

2~(NO_3^-~+~8e^-~+~6H_2O~->~NH_3~+~9OH^-)

_________________________________________

(8Zn~+~32OH^-~->8Zn(OH)_4^-^2~+~16e^-)

(2NO_3^-~+~16e^-~+~12H_2O~->~2NH_3~+~18OH^-)

Cancel out the species on both sides:

8Zn~+~14OH^-~+~2NO_3^-~+~12H_2O~-->8Zn(OH)_4^-^2~+~2NH_3

Simplifying the equation :

4Zn~+~7OH^-~+~NO_3^-~+~6H_2O~-->4Zn(OH)_4^-^2~+~NH_3

The Zn_(_s_) is <u>oxidized</u> therefefore is the <u>reducing agent</u>. The NO_3^-_(_a_q_)is<u> reduced</u> therefore is the <u>oxidizing agent</u>.

4 0
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<h2>Answer with explanation:</h2>

<em><u>Beer's Law is described as if a light passes from a solution, the concentration of the solution is directly proportional to the  absorbance of light by that solution.</u></em>

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In the testing of food, drugs or in medical testing, the light is passed from the sample.

Them transmitted light from these samples are measured. The difference between target light amount and transmitted light is the amount of absorbed light.

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Spectrophometry is based on this law.

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