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AveGali [126]
3 years ago
6

A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of

2 m and its period is measured to be 2 s. The value of g obtained in this investigation is most nearly:.
Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

<em>-</em><em> </em><em>p</em><em>e</em><em>n</em><em>d</em><em>u</em><em>l</em><em>u</em><em>m</em><em> </em><em>u</em><em>s</em><em>e</em><em> </em><em>t</em><em>o</em><em> </em><em>d</em><em>e</em><em>t</em><em>e</em><em>r</em><em>m</em><em>i</em><em>n</em><em>e</em><em> </em><em>a</em><em>c</em><em>c</em><em>e</em><em>l</em><em>e</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em>

Explanation:

<u>b</u><u>y</u><u> </u><u>c</u><u>a</u><u>l</u><u>c</u><u>u</u><u>l</u><u>a</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>n</u><u>e</u><u>e</u><u>d</u><u> </u><u>t</u><u>o</u><u> </u><u>u</u><u>n</u><u>d</u><u>e</u><u>r</u><u>s</u><u>t</u><u>a</u><u>n</u><u>d</u><u> </u><u>f</u><u>i</u><u>r</u><u>s</u><u>t</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>p</u><u>r</u><u>o</u><u>b</u><u>l</u><u>e</u><u>m</u>

<em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>n</em><em>g</em><em>t</em><em>h</em><em> </em><em>i</em><em>s</em><em> </em><em>m</em><em>e</em><em>a</em><em>s</em><em>u</em><em>r</em><em>e</em><em> </em><em>t</em><em>o</em><em> </em><em>b</em><em>e</em><em> </em><em>2</em><em>s</em>

<em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>n</em><em>g</em><em>h</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>a</em><em>l</em><em>s</em><em>o</em><em> </em><em>2</em>

<em>2</em><em> </em><em>o</em><em>b</em><em>t</em><em>a</em><em>i</em><em>n</em><em>e</em><em>r</em><em> </em><em>o</em><em>n</em><em> </em><em>i</em><em>n</em><em>v</em><em>i</em><em>s</em><em>t</em><em>i</em><em>g</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>o</em><em>s</em><em>t</em><em> </em><em>n</em><em>e</em><em>a</em><em>r</em><em>l</em><em>y</em><em> </em><em>i</em><em>s</em><em> </em><em>8</em><em>.</em>

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A long wire carries a current toward the north in a magnetic field that is directed vertically downward perpendicular to the sur
xenn [34]

The direction of the magnetic force on the wire is west.

The magnetic force acting on the moving protons acts northward in the horizontal plane. If the thumb is up (current flows vertically up), the wrapped finger will be counterclockwise.

Therefore, the direction of the magnetic field is counterclockwise. Here, the magnetic field is pointing upwards (vertical magnetic field) and the electrons are moving east. Applying Fleming's left-hand rule here, we can see that the direction of force is along the south direction.

As the change in magnetic flux increases upwards, Lenz's law indicates that the induced magnetic field of the induced current must resist and the inside of the loop must be directed downwards. Using the right-hand rule, we can see that a clockwise current is induced.

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3 0
2 years ago
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How many minutes will it take to drive to los angeles from san francisco if an average speed of 72mi/hr is maintained?
Sholpan [36]
The distance between Los Angeles and San Francisco is approximately 381.9mi. 
Divide this distance by the speed.
381.9/72 = 5.3
You are left with the time in hours. To convert to minutes, multiply by 60. 
5.3*60 = 318.25

Therefore, it will take 318.25 minutes.
6 0
3 years ago
A construction worker uses an electrical device to attract fallen nails and sharp objects
77julia77 [94]

Answer:

is the last one, a magnetic wave and electrical current moving in opposite directions

Explanation:

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3 years ago
A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru
r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

          = 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

s = u t +\dfrac{1}{2}at^2

-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

6 0
3 years ago
2. Why is it safer for a car to deform when it crashes into another car?
shepuryov [24]

Answer:

Less impact???

Explanation:

8 0
3 years ago
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