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Ne4ueva [31]
3 years ago
12

When the height of the cylinder increased by a factor of 5, from 100 m to 500 m, what happened to the cylinder’s gravitational p

otential energy?
Physics
2 answers:
Grace [21]3 years ago
8 0
PE = m*g*h ⇒ 5* PE = 5*m*g*h


storchak [24]3 years ago
4 0
It increased by a factor of 5
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an aircraft has a liftoff speed of 53 m/s. what is the minimum constant acceleration an airplane must have to reach that takeoff
xxMikexx [17]

Answer:

a=3.34\ m/s^2

Explanation:

<u>Accelerated Motion </u>

It refers to the motion of objects in which velocity is not constant over time. If the change of the velocity occurs at the same rate, then we say it's uniformly accelerated. Being   v_o= initial speed, v_f= final speed, a= constant acceleration, x= distance traveled

Then, the scalar relation between them is

v_f^2=v_o^2+2ax

The aircraft needs to reach a liftoff speed of 53 m/s from rest (assumed) having only 420 meters to do so. We can compute the acceleration by solving for a

\displaystyle a=\frac{v_f^2-v_0^2}{2x}

\displaystyle a=\frac{53^2-0^2}{2(420)}

\boxed{a=3.34\ m/s^2}

6 0
3 years ago
uniform electric field of magnitude 365 N/C pointing in the positive x-direction acts on an electron, which is initially at rest
vfiekz [6]

Answer:

a)   W = - 1.752 10⁻¹⁸ J,  b)    U = + 1.752 10⁻¹⁸ J

Explanation:

a) work is defined by

         W = F . x

the bold letters indicate vectors, in this case the force is electric

         F = q E

we substitute

         F = q E x

the charge of the electron is

         q = - e

         F = - e E x

let's calculate

         W = - 1.6 10⁻¹⁹  365  3 10⁻²

         W = - 1.752 10⁻¹⁸ J

b) the change in potential energy is

          U = q ΔV

the potential difference is

          ΔV = - E. Δs

 

we substitute

         U = - q E Δs

the charge of the electron is

           q = - e

          U = e E Δs

we calculate

           U = 1.6 10⁻¹⁹ 365  3 10⁻²

           U = + 1.752 10⁻¹⁸ J

3 0
2 years ago
Heidi (39 kg) is walking her tiny chihuahua, Chaxi (5.60 kg), on the sidewalk. To encourage Chaxi along, Heidi pulls forward wit
Ivan

Answer:

The correct reaction force in response to Heidi's action force is:

c. The friction is equal to 660 N since the beam is not accelerating.

Explanation:

Heidi's action force does not affect the beam.  Since friction resists the sliding or rolling of one solid object over another, there is no friction acting on the beam, in this respect.  The reaction force is what makes the dog to move because it acts on it.  According to Newton's Third Law of Motion, forces always come in action-reaction pairs.  This Third Law states that for every action force, there is an equal and opposite reaction force.  This means that the dog exerts some force on Heidi, as he pulls it "forward with a force of 9.55 N."

4 0
2 years ago
Which of the following statements is true?
Grace [21]
I would recommend <span>C)Organic compounds always contain carbon and hydrogen.</span>
3 0
3 years ago
You are walking up an icy slope. suddenly your feet slip, and you start to slide backward. will you slide at a constant speed, o
Aleks04 [339]
You will accelerate down the slope.
6 0
3 years ago
Read 2 more answers
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