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Ne4ueva [31]
4 years ago
12

When the height of the cylinder increased by a factor of 5, from 100 m to 500 m, what happened to the cylinder’s gravitational p

otential energy?
Physics
2 answers:
Grace [21]4 years ago
8 0
PE = m*g*h ⇒ 5* PE = 5*m*g*h


storchak [24]4 years ago
4 0
It increased by a factor of 5
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  • Radius=r=R_o/2
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We know

\boxed{\sf K.E=\dfrac{1}{2}mv^2}

For Rotational motion

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\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m(r\omega)^2

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