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dalvyx [7]
3 years ago
5

The power output of a tuba is 0.35 W. At what distance is the sound

Physics
1 answer:
STALIN [3.7K]3 years ago
8 0

The distance of the sound from the tuba is 4.82 m.

<h3>Area of the tube</h3>

The area of the tuba is calculated as follows;

I = P/A

where;

  • I is intensity of sound
  • P is power
  • A is area

A = P/I

A = 0.35 / (1.2 x 10⁻³)

A = 291.67 m²

<h3>Distance of the sound</h3>

Area = 4πr²

r = \sqrt{\frac{A}{4\pi} } \\\\r = \sqrt{\frac{291.67}{4\pi} } \\\\r = 4.82 \ m

Thus, the distance of the sound from the tuba is 4.82 m.

Learn more about intensity of sound here: brainly.com/question/4431819

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A 0.439 kg puck, initially at rest on a horizontal, frictionless surface, is struck by a 0.307 kg puck moving initially along th
lesya [120]

Answer:

u2 = 0.266 m/s

Explanation:

Let the left Puck mass at rest = m1 =0.307 Kg

mass of the right puck m2 = 0.439 kg

velocity of m1 before collision v1= 2.19 m/s

velocity of m2 before collision v2 = 0m/s

velocity of m1 after collision u1 =1.19 m/s

velocity of m2 after collision u2 = ? m/s

θ = 37°

<u>Solution:</u>

Before collision:

Momentum (y-axis ) before collision= 0 Kgm/s

Momentum (x-axis ) before collision= m1v1 + m2v2 = 0.307 Kg x 2.19 m/s + 0

= 0.672 Kgm/s

After collision:

Momentum (y-axis ) after collision= m1u1 sinθ  + m2u2 sinθ

= 0.307 x 1.19 m/s sin 37 °  + 0.439 x u2 sin 37°

= 0.22 + 0.26 u2

Momentum (x-axis ) after collision= m1u1 cosθ  + m2u2 cos θ

= 0.307 x 1.19 m/s cos 37 ° + 0.439 x u2 cos 37°

= 0.29 + 0.35 u2

According to law of conservation momentum

momentum before collision = momentum after collision.

0 + 0.672 Kgm/s =  0.22 Kgm/s  + 0.26 kg u2 + 0.29 Kgm/s + 0.35 kg u2

0.672 Kgm/s = 0.51 Kgm/s + 0.61 u2

u2 = 0.266 m/s

6 0
4 years ago
You push very hard on a heavy desk, trying to move it. You do work on the desk:
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Answer:

(C) Only if it starts moving

Explanation:

We know that work done is given by

W=F.d=Fdcos\Theta

So there are two case in which work done is zero

First case is that when force and displacement are perpendicular to each other

And other case is that when there is no displacement

So for work to be done there must have displacement, if there is no displacement then there is no work done

So option (c) will be the correct option

3 0
3 years ago
If you are lying down and stand up quickly, you can get dizzy or feel faint. This is because the blood vessels don't have time t
sammy [17]

Complete Question

If you are lying down and stand up quickly, you can get dizzy or feel faint. This is because the blood vessels don’t have time to expand to compensate for the blood pressure drop. If your brain is 0.4 m higher than your heart when you are standing, how much lower is your blood pressure at your brain than it is at your heart? The density of blood plasma is about 1025 kg/m3 and a typical maximum (systolic) pressure of the blood at the heart is 120 mm of Hg (= 0.16 atm = 16 kP = 1.6 × 104 N/m2).

Answer:

The pressure at the brain is P_b  = 89.872 \ mm \ of \ Hg

Explanation:

Generally is mathematically denoted as

                  P = \rho gh

Substituting 1025 kg/m^3 for \rho(the  density) , 9.8 m/s^2 for g (acceleration due to gravity) , 0.4m for h (the height )

We have that the pressure difference between the heart and the brain is

              P = 1025 * 9.8 *0.4

                  = 4018 N/m^2

But the pressure of blood at the heart is given as

               P_h=120 mm of Hg = 120 * 133 =  1.59*10^3Pa

Now the pressure at the brain is mathematically evaluated as

                 P_b = P_h - P

                     = 1.596*10^4 - 4018

                     = 11982 N/m^2

                      P_b= \frac{11982}{133} = 89.872 \ mm \ of \ Hg

   

     

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A 405 Hz tuning fork and a piano key are struck together, and no beats are heard. When a 402 Hz tuning fork and the same piano k
NeX [460]

The difference between the frequencies of the piano key and the tuning fork gives the frequency of the beats.

When the tuning fork is 405 Hz, and no beats are heard, then the piano key is also 405 Hz.

When the piano key is 405 Hz and the tuning fork is 402 Hz, then 405 - 402 = 3 beats are heard.

The piano key is 405 Hz.

4 0
4 years ago
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