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slega [8]
3 years ago
6

If spring has a spring constant of 500 N/m and is stretched .50 meters,how much energy is stored in the spring ((show work for f

ull credit, show equation))
Physics
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer:

The energy stored is: 62.5 Joules

Explanation:

Given

k = 500N/m --- spring constant

x = 0.5m --- stretch

Required

The amount of energy

This is calculated as:

U = \frac{1}{2} kx^2

U = \frac{1}{2} * 500N/m * (0.5m)^2

U = 250N/m * (0.5m)^2

U = 62.5\ J

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Answer:

d = 5.10 m

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