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3 years ago

Which statement below best describes the temperature of the atmosphere at various altitudes?

2 answers:

5 0

The correct option is A. The atmosphere is divided into four layers, which are troposphere, stratosphere, mesophere and thermosphere. In all these layers, temperature changes with changes in altitude. Of all these atmospheric layers, mesophere is the coldest; temperature in mesophere decreases with increasing altitude to about -100 degree Celcius.

SVEN [57.7K]3 years ago

5 0

Answer:

A). The mesophere has a lower temperature than the thermosphere.

Explanation:

At the mesophere, the temperature decreases with height, reaching a minimum of about -90°C at the "mesopause". As we rise up in the mesophere, the temperture becomes colder and colder. Above the mesophere is the thermosphere, where variations in the sun's energy have a powerful influence on both the height of the top layer of the thermosphere and the temperature within it. Because of this, temperatures of the upper layer of thermosphere can vary from 500° C (932° F) to 2,000° C (3,632° F) or higher.

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Calculate the energy released in each of the following fusion reactions. Give your answers in MeV. (a) 2H + 3H → 4He + n 17.54 C

Vikentia [17]

Answer:

a) E = 17.55 MeV

b) E = 18.99 MeV

c) E = 3.29 MeV

d) You can use the methods applied for the other parts to solve this, the equation is not properly written

e) E = 4.075 MeV

Explanation:

Energy Released, $E = \triangle M * 931.5$

$\triangle M = \sum M_{product} - \sum M_{reactant}$

Mass of 1H, $M_{H} = 1.007823$

Mass of 2H, $M_{2H} = 2.0141u$

Mass of 3H, $M_{3H} = 3.016 u$

Mass of Helium, $M_{4He} = 4.002602u$

Mass of Beryllium, $M_{7Be} = 7.01693 u$

Mass of neutron, $M_{n} = 1.008664 u$

a) $2H + 3H \rightarrow 4He + n$

$\triangle M = (4M_{He} + M_{n} ) - (2M_{H} + 3 M_{H} )\\\triangle M = ( 4.0026 + 1.008664) - (2.0141 + 3.016 )\\\triangle M = -0.01884u$

Energy released,

$E = -0.01884 * 931.5\\E = -17.55 Mev$

Energy released = 17.55 MeV

b) $4He + 4He \rightarrow 7Be + n$

$\triangle M = (M_{7Be} + M_{n} ) - (M_{4He} + M_{4He} )\\\triangle M = ( 7.01693 + 1.008664) - (4.002602 + 4.002602 )\\\triangle M = 0.02039 u$

Energy released,

$E = 0.02039 * 931.5\\E = 18.99 Mev$

c) $2H + 2H \rightarrow 3 He$ + n

$\triangle M = (M_{3He} + M_{n} ) - (M_{2H} + M_{2H} )\\\triangle M = ( 3.016 + 1.008664) - (2.0141 + 2.0141 )\\\triangle M = -0.003536 u$

Energy released,

$E = -0.003536 * 931.5\\E = -3.29 Mev$

E = 3.29 MeV(Energy is released)

d) You can use the methods applied for the other parts to solve this, the equation is not properly written

e) $2H + 2H \rightarrow 3H + 1H$

$\triangle M = (M_{3H} + M_{1H} ) - (M_{2H} + M_{2H} )\\\triangle M = ( 3.016 + 1.007825) - (2.0141 + 2.0141 )\\\triangle M = -0.00435 u$

$E = -0.00435 * 931.5\\E =-4.075 Mev$

E = 4.075 MeV ( Energy is released)

5 0

3 years ago

Calculate the mass of nitric acid required to make a 250mL solution with 2.40 ph

meriva

The mass of nitric acid required to make the given solution is 0.0627 g.

The given parameters:

Volume of the acid, V = 250 mL
pH of the acid, = 2.4

The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

$H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398$

The molarity of the nitric acid is calculated as follows;

$= 0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M$

The number of moles of the nitric acid is calculated as follows;

$moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.$

The molar mass of nitric acid is calculated as;

$HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol$

The mass of the nitric acid contained in the calculated number of moles is calculated as;

$mass = moles\ \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g$

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.

Learn more about molarity of acids here: brainly.com/question/13864682

3 0

2 years ago

Which planet is sometimes called Uranus’s twin? Saturn Pluto Jupiter Neptune

sattari [20]

Neptune.

Because the size, mass, composition and rotation of Neptune and Uranus are very similar they're sometimes refered to as planetary twins.

7 0

3 years ago

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Describe how functional groups affect an organic molecule's' chemical reactivity

vazorg [7]

Functional groups are set of commonly found groups of atoms covalently bonded to carbon in organic molecules.The unique functional groups present on a bio molecule determine reactivity solubility and other physical properties that lead to its biological role in living organisms.

4 0

3 years ago

What is the empirical formula for a compound that has 57.5%

Rainbow [258]

Answer:

Explanation:

use %composition given to calculate emperical 4mular

8 0

3 years ago