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r-ruslan [8.4K]
4 years ago
13

How many molecules are in 2.50 moles of h2o

Chemistry
2 answers:
White raven [17]4 years ago
4 0

Explanation:

According to the mole concept there are 6.022 \times 10^{23} atoms or molecules are present in 1 mole of a substance.

Mathematically,    1 mole = 6.022 \times 10^{23} atoms or molecules

Therefore, calculate the number of molecules present in 2.50 moles of H_{2}O as follows.

            2.50 mol \times 6.022 \times 10^{23}}molecules/mol

                  = 15.055 \times 10^{23} molecules

Thus, we can conclude that there are 15.055 \times 10^{23} molecules in 2.50 moles of H_{2}O.

aivan3 [116]4 years ago
3 0
To find out how many molecules you have, you need to multiply the number of moles with Avogadros constant: 2.50 * 6.022 * 10²³ = 1.5055 * 10^24.
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How many grams of iron are needed to produce 3 g of iron(III) chloride?
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Answer:

5 its just what i do

Explanation:

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3 years ago
The half-life of radon gas is approximately four days. Four weeks after the introduction of radon into a sealed room, the fracti
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The fraction of the original amount remaining is closest to 1/128

<h3>Determination of the number of half-lives</h3>
  • Half-life (t½) = 4 days
  • Time (t) = 4 weeks = 4 × 7 = 28 days
  • Number of half-lives (n) =?

n = t / t½

n = 28 / 4

n = 7

<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 100 g
  • Number of half-lives (n) = 7
  • Amount remaining (N)=?

N = N₀ / 2ⁿ

N = 100 / 2⁷

N = 0.78125 g

<h3>How to determine the fraction remaining </h3>
  • Original amount (N₀) = 100 g
  • Amount remaining (N)= 0.78125 g
  • Fraction remaining =?

Fraction remaining = N / N₀

Fraction remaining = 0.78125 / 100

Fraction remaining = 1/128

Learn more about half life:

brainly.com/question/26374513

7 0
2 years ago
Combustion vapor-air mixtures are flammable over a limited range of concentrations. The minimum volume % of vapor that gives a c
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Combustion equation of n-hexane:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

a)
Assuming we have 100 moles of air,
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n-hexane required = 20.9/19 x 2
= 2.2 moles

LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1% 

b)
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6 0
3 years ago
Read 2 more answers
You are asked to write observations about a 100g sample of Nitrogen-16 before it decays, but you're running late. In order to ma
san4es73 [151]

Answer:

You cannot make observations if you are 57 seconds late into the lab.

Explanation:

The atomic nucleus can split by decay into 2 or more particles as a result of the instability of its atomic nucleus due to the fact that radioactive elements possess an unstable atomic nucleus.

Now, the primary particles which are emitted by radioactive elements in order to make them decay are alpha, beta & gamma particles.

The half life equation is;

N_t = N₀(½)^(t/t_½)

Where:

t = duration of decay

t_½ = half-life

N₀ = number of radioactive atoms initially

N_t = number of radioactive atoms remaining after decay over time t

We are given;

t = 57 secs

N₀ = 100 g

Now, half life of Nitrogen-16 from online sources is 7.2 seconds. t_½ = 7.2

Thus;

N_t = 100(1/2)^(57/7.2)

N_t = 0.4139g

We are told that In order to make observations, you require at least .5g of material.

The value of N_t you got is less than 0.5g, therefore you cannot make observations if you are 57 seconds late.

5 0
3 years ago
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<u>Answer:</u> The chemical formula of Iron (III) sulfate is Fe_2(SO_4)_3

<u>Explanation:</u>

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To form Fe^{3+} ion, this element will loose 3 electrons.

Sulfate ion is a polyatomic ion having chemical formula of SO_4^{2-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfate is Fe_2(SO_4)_3

4 0
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