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nlexa [21]
2 years ago
8

20 points!!!!!!Gravity would cause the rain falling in which two locations to drain an into area a. I’m assuming it’s 1 and 5 bu

t still ( I have to pick two answers btw)
A.1
B.2
C.3
D.5

Chemistry
1 answer:
zimovet [89]2 years ago
7 0

Answer:

youre right i think its 1 and 5

because it cant be 2 or 3

Explanation:

I hope this answers your question(s). Have a good weekend!

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Explain the relationship between monomers and polymers using polysaccharides as an example
Mars2501 [29]

Answer:

Glucose and glycogen.

Explanation:

Hello,

Monomers are the functional molecules forming the polymers when an random amount of units (monomers) are linked form an assembly (polymer).

This could be exposed by considering the glucose as the monomer forming the glycogen which is a polymer that serves as a form of energy storage in animals, fungi, and bacteria; it is constituted by about 30,000 units of both lineal and branched glucose which provide many features that the glucose doesn't have by itself.

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7 0
4 years ago
Phytoplankton are microscopic photosynthesizing organisms that typically live in the upper layers of the ocean. What trophic lev
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I think they are primary producers, as they produce biomass from inorganic compounds (CO2)
8 0
3 years ago
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What type of stress is caused by two plates sliding past one another?
NISA [10]
That stress is compression. It forms Reverse Faults.
7 0
4 years ago
Equal molar amounts of H2 and I2 are placed into an evacuated container and heated to 445°C, where the following equilibrium is
Rus_ich [418]

<u>Answer:</u> The initial concentration of H_2\text{ and }I_2 are 0.0192 M and 0.0192 M respectively.

<u>Explanation:</u>

We are given:

Equilibrium concentration of HI = 0.030 M

Moles of hydrogen gas = Moles of iodine gas (concentration will also be the same)

For the given chemical equation:

                  H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>            x     x        -

<u>At eqllm:</u>     x-c    x-c     2c

Calculating the value of 'c'

2c=0.030\\\\c=\frac{0.030}{2}=0.015M

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[HI]^2}{[H_2]\times [I_2]}

We are given:

K_{eq}=50.2

[H_2]=(x-c)=(x-0.015)

[I_2]=(x-c)=(x-0.015)

Putting values in above equation, we get:

50.2=\frac{(0.030)^2}{(x-0.015)\times (x-0.015)}\\\\x=0.0108,0.0192

Neglecting the value of x = 0.0108 M, because the initial concentration cannot be less than the equilibrium concentration.

x = 0.0192 M

Hence, the initial concentration of H_2\text{ and }I_2 are 0.0192 M and 0.0192 M respectively.

5 0
3 years ago
URGENT PLS HELP!!!!!
aksik [14]

Answer:

+2

Explanation:

Elements in group 2A have 2 valence electrons in their outer shell, so when they bond with other atoms, they are most likely to give away these 2 electrons. With 2 electrons gone, the ion will have a positive charge (since there are now more protons than electrons in the atom).

5 0
3 years ago
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