Answer:
Glucose and glycogen.
Explanation:
Hello,
Monomers are the functional molecules forming the polymers when an random amount of units (monomers) are linked form an assembly (polymer).
This could be exposed by considering the glucose as the monomer forming the glycogen which is a polymer that serves as a form of energy storage in animals, fungi, and bacteria; it is constituted by about 30,000 units of both lineal and branched glucose which provide many features that the glucose doesn't have by itself.
Best regards.
I think they are primary producers, as they produce biomass from inorganic compounds (CO2)
That stress is compression. It forms Reverse Faults.
<u>Answer:</u> The initial concentration of
are 0.0192 M and 0.0192 M respectively.
<u>Explanation:</u>
We are given:
Equilibrium concentration of HI = 0.030 M
Moles of hydrogen gas = Moles of iodine gas (concentration will also be the same)
For the given chemical equation:

<u>Initial:</u> x x -
<u>At eqllm:</u> x-c x-c 2c
Calculating the value of 'c'

The expression of
for above reaction follows:
![K_{eq}=\frac{[HI]^2}{[H_2]\times [I_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5Ctimes%20%5BI_2%5D%7D)
We are given:

![[H_2]=(x-c)=(x-0.015)](https://tex.z-dn.net/?f=%5BH_2%5D%3D%28x-c%29%3D%28x-0.015%29)
![[I_2]=(x-c)=(x-0.015)](https://tex.z-dn.net/?f=%5BI_2%5D%3D%28x-c%29%3D%28x-0.015%29)
Putting values in above equation, we get:

Neglecting the value of x = 0.0108 M, because the initial concentration cannot be less than the equilibrium concentration.
x = 0.0192 M
Hence, the initial concentration of
are 0.0192 M and 0.0192 M respectively.
Answer:
+2
Explanation:
Elements in group 2A have 2 valence electrons in their outer shell, so when they bond with other atoms, they are most likely to give away these 2 electrons. With 2 electrons gone, the ion will have a positive charge (since there are now more protons than electrons in the atom).