If you are provided with Cation and an Anion with different oxidation states, then there ratio in the formula unit is adjusted as such that the oxidation number of one ion is set the coefficient of other ion and vice versa,
Example:
Let suppose you are provided with A⁺² and B⁻¹, so multiply A by 1 and B by 2 as follow,
A(B)₂
In statement we are given with Co⁺³ and SO₄⁻², so multiply Co⁺³ by 2 and SO₄⁻² by 3, hence,
Co₂(SO₄)₃
Result:
Co₂(SO₄)₃ is the correct answer.
The boiling point of oxygen is higher than nitrogen's boiling
The reason the boiling point of O2 is higher is not because of increased van der Waals interactions, but simple physics. The mass of a molecule of O2 is greater than that of a molecule of N2, so the molecule of O2 traveling at a speed sufficient to break out of the liquid phase has a greater kinetic energy than an analogous N2 molecule.
The net effect is that more energy must be distributed throughout a sample of O2 to achieve a given vapor pressure (in this case equal to atmospheric pressure) than for a sample of N2. More energy means greater temperature.
The balanced equation will be 
<h3>Stoichiometric problems</h3>
The balanced equation of the reaction would be as follows:
The mole ratio of methane to carbon dioxide is 1:1.
10 grams of methane will give 10/16 = 0.625 moles
0.625 moles of carbon dioxide would give 0.625 x 44.01 = 27.506 grams.
Thus, 10 grams of methane will produce approximately 27 grams of carbon dioxide stoichiometrically.
The reaction obeys the law of conservation of mass because the atoms of all the elements before and after the reaction are balanced.
More on stoichiometric problems can be found here: brainly.com/question/14465605
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Answer:
Top left: RR Top right: Rr Bottom left: Rr Bottom right: rr
Explanation:
if both parents are heterozygous then the table will always look like this. the chances of the offspring being heterozygous are 50%. the offspring has a 25% chance of having two recessive traits and a 25% chance of having two dominant traits.
