Why does LiCl does not exhibit frenkel defect?

1 answer:

3 0

Frenkel defect is a defect in crystalline solids in which an atom is displaced from its lattice position to an interstitial space. This creates a vacant space at the original site and an interstitial defect at the new site within the same element. This defect does not affect the chemical properties of the compound. This defect usually occur in ionic solids with large size difference between the anion and cation.
LiCl does not exhibit Frenkel defect because the size difference between the anion and the cation of the compound is very small.

You might be interested in

Consider the two electron arrangements for neutral atoms A and B. The outer electron of atom B has moved to a higher energy stat

romanna [79]

B I think the answer

6 0

3 years ago

Please help!!!! ⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️

Bumek [7]

Polyatomic ions: $CH_3COO^-$ , $NO_3^-$ , $NH^+$ , $CN^-$ , $Li^+$ , and $OH^-$

Monatomic ions: $Ca^{2+$ , $O^{2-$ , and $Fe^{3+$

<h3>Monoatomic vs Polyatomic Ions</h3>

In chemistry, monoatomic ions are ions that consist of only a single type of atom. They are usually positive or negatively charged and are otherwise known as simple ions. Examples include $Ca^{2+$ , $O^{2-$ , and $Fe^{3+$

Polyatomic ions, on the other hand, are ions that consist of more than one atom, unlike monoatomic ions. The two or more atoms are covalently bonded and the entire structure behaves like a single chemical entity in reactions. Polyatomic ions are otherwise known as molecular ions.

Examples of polyatomic ions are $CH_3COO^-$ , $NO_3^-$ , $NH^+$ , $CN^-$ , $Li^+$ , and $OH^-$

Thus, from the diagram:

Polyatomic ions: $CH_3COO^-$ , $NO_3^-$ , $NH^+$ , $CN^-$ , $Li^+$ , and $OH^-$

Monatomic ions: $Ca^{2+$ , $O^{2-$ , and $Fe^{3+$

More on ions can be found here: brainly.com/question/14982375

#SPJ1

6 0

1 year ago

The electron configuration of bromine is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 classify electrons in each.

bulgar [2K]

Bromine has the following electron configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5. categorize the electrons in each. Answer for video: The video player is loaded.

On the periodic chart, row 5, column 7, is where you can find a chemical element that was identified in 1811. It has a proton count of 53 and an atomic mass of 126.9. Iodine's atom, then, contains 53 electrons in the following configuration: 1s2, 2s2, 2p6, 3s2, 3d10, 4p6, 5s2, 4d10, 5p5 (Kr 4d10 5s2 5p5). Cu Z = 29 has an electrical arrangement of 1s2 2s2 2p6 3s2 3p6 3d10 4s1. Copper (Co) has the following electron configuration: 1s2 2s2 2p6 3s3 3p6 4s2 3d7. If a chemist were to refer to Copper by its subshell, they would abbreviate this notation to "3d7."

To learn more about electrons please click on below link

brainly.com/question/1255220

#SPJ4

7 0

1 year ago

You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from

GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$