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MAVERICK [17]
3 years ago
15

A jet of water squirts out horizontally from

Physics
2 answers:
Paul [167]3 years ago
7 0

Answer:

the answer is 6.06

t=0.501

s

v=x/t

0.5pv²=pgh

h=v²/2g= 1.09²/2(9.8)=0.0606 m=6.06 cm

Bond [772]3 years ago
5 0
The correct answer to your question is 3.62
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What can make your computer "sick"?
Svetach [21]

Answer:

An virus

Explanation:

An computer virus can come from websites that try to steal your Information or apps that's not necessarily scanned and protected so that yor computer can be safe from viruses.

7 0
3 years ago
Black holes are highly condensed remnants of stars. Some black holes, together with a normal star, form binary systems. In such
borishaifa [10]

\lambda_\text{max} = 2.63\times 10^{-9}\;\text{m}.

<h3>Explanation</h3>

The peak emission wavelength of an object depends on its absolute temperature.

\lambda_\text{max} = \dfrac{2.90\times 10^{-3}}{T},

where

  • \lambda_\text{max} is the wavelength in meters where the emission is the strongest.
  • T is the temperature of the object in degrees Kelvins.

For the gas falling into the black hole,

T = 1.10\times 10^{6}\;\text{K}.

Apply the formula:

\lambda_\text{max} = \dfrac{2.90\times 10^{-3}}{T} = \dfrac{2.90\times 10^{-3}}{1.10\times 10^{6}} = 2.64\times 10^{-9}\;\text{m} = 2.64 \;\text{nm}.

The question mentioned that \lambda_\text{max} is in the X-ray region of the electromagnetic spectrum. According to Encyclopedia Britannica, the wavelength of X-rays range from 10^{-8}\;\text{m}=10\;\text{nm} to 10^{-10}\;\text{m} = 0.1\;\text{nm}, which indeed includes 2.64\times 10^{-9}\;\text{m} = 2.64 \;\text{nm}.

4 0
3 years ago
Pls help thx need asap!!
torisob [31]

Answer:

10N right

Explanation:

First, we need to find the base of the triangle to find the force acting on the right of the object.

  • We have been given the hypotenuse and we need to find the adjacent, so we are using cos
  • SOH, CAH, TOA
  • cos(θ) = adjacent ÷ hypotenuse

Next, sub in the values (we don't know the adjacent so i've called it x):

  • cos(60) = x ÷ 60

To find x, we need to multiply both sides by 60

  • 60 × cos(60) = x
  • x = 30 N

Now we know all the forces, we can work out the net force:

  • Both of the 40N cancel out because they are opposite forces
  • The force on the right of the object is 10N stronger than the force on the left (30N - 20N), so the object would move to the right

8 0
3 years ago
Consider the Bose-Einstein distribution: F60 per unit energy can be written as N aE 6.) (20pts) Assuming BE &lt;&lt;1,obtain an
notsponge [240]

Answer:

Explanation:

Whacbdhnd

4 0
3 years ago
A virtual image is formed 17.0 cm from a concave mirror having a radius of curvature of 39.0 cm. (a) Find the position of the ob
Wittaler [7]

Explanation:

Image distance, v = -17 cm (-ve for virtual image)

Radius of curvature of concave mirror, R = 39 cm

Focal length, f = -19.5 cm (-ve for a concave mirror)

(a) Using mirror's formula as :

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}

\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}

\dfrac{1}{u}=\dfrac{1}{-19.5}-\dfrac{1}{(-17)}  

u = 132.6 cm    

So, the object is placed 132.6 cm in front of the mirror.

(b) Magnification of the  mirror, m=\dfrac{-v}{u}

m=\dfrac{-17}{132.6}

m = -0.128

Hence, this is the required solution.

7 0
4 years ago
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