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Levart [38]
3 years ago
14

calculate speed and velocity of the following. the race car was moving for 3.7 hours and during that time it traveled a distance

of 500 miles south. what is the speed the car was travelling?
Physics
1 answer:
Ksju [112]3 years ago
7 0

Answer:

v = 135.13 mph

Explanation:

Given that,

The race car was moving for 3.7 hours and during that time it traveled a distance of 500 miles south.

We need to find the speed of the car.

We know that,

Speed = distance/time

So,

v=\dfrac{500\ miles}{3.7\ h}\\\\v=135.13\ mph

So, the speed of the car is equal to 135.13 mph.

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A 62.0-kg athlete leaps straight up into the air from a trampoline with an initial speed of 9.6 m/s. The goal of this problem is
pochemuha

Answer:

2856.96 J

0

0

\frac{1}{2}mv_i^2+mgh_i=\frac{1}{2}mv_f^2+mgh_f

6.78822 m/s

Explanation:

v_i = Initial velocity = 9.6 m/s

g = Acceleration due to gravity = 9.81 m/s²

h = Height

The athlete only interacts with the gravitational potential energy. Air resistance is neglected.

At height y = 0

Kinetic energy

K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times 62\times 9.6^2\\\Rightarrow K=2856.96\ J

At height y = 0 the potential energy is 0 as

P=mgy\\\Rightarrow P=mg0=0

At maximum height her velocity becomes 0 so the kinetic energy becomes zero.

As the the potential and kinetic energy are conserved

The general equation

K_i+P_i=K_f+P_f\\\Rightarrow \frac{1}{2}mv_i^2+mgh_i=\frac{1}{2}mv_f^2+mgh_f

Half of maximum height

\\\Rightarrow mgh_i+\frac{1}{2}mv_f^2=mg\frac{h_i}{2}+\frac{1}{2}mv^2\\\Rightarrow gh_i=g\frac{h_i}{2}+\frac{1}{2}v^2\\\Rightarrow g\frac{h_i}{2}=\frac{1}{2}v^2\\\Rightarrow v=\sqrt{gh}

h_i=\frac{v_i^2}{2g}

v=\sqrt{gh}\\\Rightarrow v=\sqrt{g\times \frac{v_i^2}{2g}}\\\Rightarrow v=\sqrt{\frac{v_i^2}{2}}\\\Rightarrow v=\sqrt{\frac{9.6^2}{2}}\\\Rightarrow v=6.78822\ m/s

The velocity of the athlete at half the maximum height is 6.78822 m/s

8 0
2 years ago
Please help me on this
Dafna1 [17]
I’m pretty sure the answer is A
5 0
3 years ago
What is the kinetic energy of a 1.00g hailstone falling at 8.50m/s
bearhunter [10]

Answer:

36.125 J

Explanation:

The formula for kinetic energy is KE = .5(m)(v²).

Using the given information, mass = 1 g and v = 8.50.  Plug that information into the equation.  KE = .5(1)(8.50²) = 36.125 J.

4 0
3 years ago
If you push a 900N refrigerator with the same force as you lift a 40N dumbbell, the dumbbell will move faster. Which of Newton’s
svetlana [45]

This is Newton's second law of motion.

It states that Force exerted on a moving object is directly proportional to its product of mass and acceleration.

i.e Force(F) = Mass(M) × Acceleration(A)

Because Force is constant here, reducing the weight of the body the force is applied to consequently reduces its mass.

If mass is reduced, the body's acceleration increases hence increasing its speed.

That is why the 40N dumbbell move faster.

3 0
3 years ago
why is it that when the moon is farthest away from the sun, its the brightest? shouldn't it be the darkest if the earth's shadow
professor190 [17]
Of my knowlaedge, the suns light rays are so intense that they bounce off of other planets and shine on the face of the moon giving us the ability ti see the moon at night.
4 0
3 years ago
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