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Elis [28]
3 years ago
12

Explain the characteristics of the Gypsum Hills regionIf we have a sample of silicon (Si) atoms that has 14 protons, 14 electron

s, and 18 neutrons
What is the name of this specific silicon isotope?

silicon-14
silicon-32
silicon-46
silicon-153
Physics
1 answer:
amid [387]3 years ago
8 0

Answer:

second one

Explanation:

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A 80 kg parent and a 20 kg child meet at the center of an ice rink. They place their hands together and push. The parent pushes
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Answer:

force acting on the parent = 25 N .

Explanation:

According to third law of Newton , there is equal and opposite reaction to every action . Here force by the parent on child is action and the force by child on parent is reaction . The former is given as 25 N so force by child on parent will also be 25 N .

Answer is 25 N .

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Calculate the weight of a 25kg object?
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Mass of 25 kg weight is 25/9.81 slug of mass.
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Circle the statements that indicate a chemical property.
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C) because a new substance is formed
B) not sure but might be because the chemical properties of the substance has changed
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Which objects would be considered to be in free fall?
SVEN [57.7K]

Answer:

Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.

Explanation:

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3 years ago
Read 2 more answers
n alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 5.94 cm in a uniform magnetic field with B = 1.10 T.
9966 [12]

Answer:

a). V = 3.13*10⁶ m/s

b). T = 1.19*10^-7s

c). K.E = 2.04*10⁵

d). V = 1.02*10⁵V

Explanation:

q = +2e

M = 4.0u

r = 5.94cm = 0.0594m

B = 1.10T

1u = 1.67 * 10^-27kg

M = 4.0 * 1.67*10^-27 = 6.68*10^-27kg

a). Centripetal force = magnetic force

Mv / r = qB

V = qBr / m

V = [(2 * 1.60*10^-19) * 1.10 * 0.0594] / 6.68*10^-27

V = 2.09088 * 10^-20 / 6.68 * 10^-27

V = 3.13*10⁶ m/s

b). Period of revolution.

T = 2Πr / v

T = (2*π*0.0594) / 3.13*10⁶

T = 1.19*10⁻⁷s

c). kinetic energy = ½mv²

K.E = ½ * 6.68*10^-27 * (3.13*10⁶)²

K.E = 3.27*10^-14J

1ev = 1.60*10^-19J

xeV = 3.27*10^-14J

X = 2.04*10⁵eV

K.E = 2.04*10⁵eV

d). K.E = qV

V = K / q

V = 2.04*10⁵ / (2eV).....2e-

V = 1.02*10⁵V

7 0
3 years ago
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