There are 3 feet in a yard so divide 27 by 3 to get 9 yards
Answer:
Train A = 214
Train B = 86
Step-by-step explanation:
a + b = 300
a - b = 128
a + b = 300
a = 128 + b
(128 + b) + b = 300
128 + b + b = 300
128 + 2b = 300
2b = 300 - 128
2b = 172
b = 172 ÷ 2
b = 86
a = 128 + b
a = 128 + (86)
a = 214
Answer:
983040
Step-by-step explanation:
Second Year : 15x4=60
Third Year : 60x4=240
Fourth Year : 240x4=960
Fifth Year : 960x4=3840
Sixth Year : 3840x4=15360
Seventh Year : 15360x4 = 61440
Eighth Year: 61440x4=245760
Ninth Year : 245760x4= 983040
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
Answer:
$750
Step-by-step explanation:
We can set up the equation 30x + 50y = z where x = the amount of small dogs, y = the amount of big dogs, and z = the total.
After plugging in the x and y values to solve for z, we are left with the following equation:
30(15) + 50(6) = 750
