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taurus [48]
4 years ago
12

During a transcranial magnetic stimulation (TMS) treatment, a magnetic field, typically of magnitude 5.00 T, is produced in the

brain using external coils. During the treatment, the current in the coils (and hence the magnetic field in the brain) rises from zero to its peak in about 70.0 μs. Assume that the magnetic field is uniform over a circular area of diameter 2.00 × 10-2 m inside the brain. What is the magnitude of the average induced emf around this region of the brain during the treatment?
Physics
1 answer:
olchik [2.2K]4 years ago
7 0

Answer:

The magnitude of the average induced emf is 22.43 V.

Explanation:

Given that,

Magnetic field = 5.00 T

Diameter = 2.00\times10^{-2} m

Current I= 70.0\ mu s

We need to calculate the area

Using formula of area

A=\pi r^2

A=3.14\times(\dfrac{2.00\times10^{-2}}{2})^2

A=0.000314\ m^2

We need to calculate the induced emf

Using formula of induced emf

\epsilon=A\dfrac{dB}{dt}

\epsilon=0.000314\times\dfrac{5.00-0}{70.0\times10^{-6}}

\epsilon=22.43\ V

Hence, The magnitude of the average induced emf is 22.43 V.

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7 0
3 years ago
Read 2 more answers
The magnetic field is decreasing. What is the induced electric field?
melisa1 [442]

Answer: The induced electric field will be constant i.e zero

Explanation:

Magnetic field is a region of space where magnetic force can be felt while electric field is a region of space where electric force can be felt. This two field are related because they tend to talk about force of attraction and repulsion. Example is running a current through a thin wire near a magnet, the direction of one of the field will determine the direction of the other.

According to the question, if the magnetic field is decreasing, the electric field will adjust by traveling in opposite direction to the magnetic field just to make the field constant.

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3 years ago
How do we use soil to generate electricity?
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3 years ago
A 10-cm-thick aluminum plate (α = 97.1 × 10−6 m2/s) is being heated in liquid with temperature of 475°C. The aluminum plate has
Anuta_ua [19.1K]

Answer:

T_0 = 338.916 Degree\ celcius

Explanation:

Given data:

Thickness of aluminium sheet 10 cm

initial temperature = 25 degree celcius

Assumption

Thermal properties remain constant, transfer of heat by radiation is negligible.

from the information given in the question we have

T_S ≈T_∞ , it implies we have h → ∞

from table 4.2 Biot number → ∞ the value of

\lambda_1 = 1.5708 and A_1= 1.2732

The fourier number is

t = \frac{\alpha t}{l^2} = \frac{97.1\times 10^{-6} \times 15}{0.05^2} = 0.5826

Temperature at center after 15 second of heating

\theta _{0 wall} = \frac{T_0 - T_{\infity}}{T_i -T_{\infity}} = A_i e^{\lambda_1^2 t}

T_0 = T_i -T_{\infity} \times A_i e^{\lambda_1^2 t}

T_0 = (25 - 475) 1.2732 e^{-1.5708^2 \times 0.5826} +  475  = 356 degree celcius

T_0 = 338.916 Degree\ celcius

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What is the amount of force required to accelerate a 20 kg object to 5 m/s˛?
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Answer:

Force = 100N

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