Answer:

Explanation:
Given that,
Initial speed of a shuttlecock, u = 30 m/s
Final speed of the shuttlecock, v = 10 m/s
Time, t = 0.5 s
We need to find its average acceleration. The acceleration of an object is equal to the change in speed divided by time taken. It is given by :

So, the average acceleration of badminton shuttlecock is
.
Answer:
2.72×10^-7
Explanation:
velocity = frequency × wavelength
2.05×10^8=7.55×10^14 wavelength
wavelength = 2.05×10^8/7.55×10^14
wavelength = 2.72×10^-7
As the skydiver accelerates she gains momentum, and the air she passes through creates a resistance that pushes back up at her, increasing drag. Eventually, the force of the resisting air balances out with the force of gravity, and the skydiver stops speeding up
Answer:
Torque on the coil will be ZERO
Explanation:
As we know that the magnetic moment of the closed current carrying coil is always along its axis and it is given as

now we know that magnetic field is also along the axis of the coil so here as we know the equation of torque given as

so we have


<em><u>Primary coil:</u></em><em><u /></em><u />
It is the part of electric circuit in which input voltage is applied,,and it induces current in neighbouring secondary coil...
<em><u>Secondary coil:</u></em><em><u /></em><u />
It is the coil in which current is induced by primary coil...