How to balance this equation with algebraic method ( please include explanation )

Calculate the molar mass of Cu2CO3 in grams per mole or search for a chemical formula or substance. Molecular weight of Cu2CO3. ... Copper: Cu: 63.546: 2: 67.927%: Carbon: C: 12.0107: 1: ... it tells us how many grams …

6 0

2 years ago

If enzymatic reactions could actually be carried out at high temperatures, what would you expect for the rate of the catalyzed r

likoan [24]

Answer:

Temperature of 100°C increase the reaction rate, due to the rise of the energetic collision between molecules that increase the collision, compared to the same reaction at 21 °C, who has less energy and for that reason will be more slow to react.

Explanation:

The enzymatic reactions are reactions between organic molecules named as substrate and some proteic biological structures called enzymes. These reactions can be simplified as a regular chemistry process between reagents to obtain a product, that in this case is the transformations of the substrate.

So we can use the following process:

Enzyme (E) + substrate (S) = product (P)

Of course, this an uncomplex way to see this process, just to understand this example. In reality, the product or these reactions involves a transformation of the substrate and the enzyme. But for now, let's just use this equation

Using just the letters:

E + S = P

Now, we can use the concept of rate or velocity on chemical equations to analyze the effect of temperature in the enzymatic reactions:

Remember that for any chemistry reactions, the rate depends on the capacity of the molecules to collide, these collisions will be major when the reagents have enough kinetic energy to move around and interact between them. The frequency of these collisions is affected by different variables such as temperature.

Temperature is equal to energy, so if to reactions are supplied by external energy like thermic energy, the molecules, in this case, enzyme and substrate can move faster, and the collides can be more frequent when the temperature increases.

In conclusion, the increases in temperature to 100°C, increase the reaction rate, due to the rise of the energetic collision between molecules that increase the collision, and are these who result in the product of a enzymatic reactions, compared to the same reaction at 21 °C, who has less energy and for that reason will be more slow to react.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=MnO_4%5E-%20%28aq%29%20%2B%20H_2C_2O_4%20%28aq%29%20%5Crightarrow%20Mn_2%5E%2B%20%28aq%29%20%2

Veseljchak [2.6K]

Answer:

1. C has been oxidized in the reaction.

2. Mn has been reduced in the reaction.

3/4 The reducing agent is the C and the oxidizing agent is the Mn.

The reaction in an acidic solution is:

16H⁺ + 2MnO₄⁻ + 5C₂O₄⁻² → 10CO₂ + 2Mn²⁺ + 8H₂O

10 moles of electrons are been transferred.

Explanation:

MnO₄⁻ (aq) + H₂C₂O₄ (aq) → Mn²⁺ (aq) + CO₂ (g)

In the permanganate, Mn acts with +7 as oxidation number, and in product side, we have Mn2+. It has decrease the oxidation number, so it has been reduced. This is the oxidizing agent.

In the oxalic acid, carbon has +3 as oxidation number, and in CO2, we see that acts with +4 so, it has increase it. This element is the reducing agent and has been oxidated.

8H⁺ + MnO₄⁻ + 5e⁻ → Mn²⁺ + 4H₂O

It is completed on the opposite side where there are oxygen, with as many water as there are oxygen, and on the opposite side complete with protons to balance the H

C₂O₄⁻² → 2CO₂ + 2e⁻

In oxalate, the carbon that acted with +3 gained an electron to oxidize to +4, but since there are 2 carbons, it gained 2 electrons. The oxygen is balanced by adding a 2 in stoichiometry

The halfs reaction have to be multipplied .2 (reduction) and .5 (oxidation) to balance the electrons in the main equation.

(8H⁺ + MnO₄⁻ + 5e⁻ → Mn²⁺ + 4H₂O) . 2

(C₂O₄⁻² → 2CO₂ + 2e⁻ ) . 5

16H⁺ + 2MnO₄⁻ + 10e⁻ + 5C₂O₄⁻² → 10CO₂ + 10e⁻ + 2Mn²⁺ + 8H₂O

16H⁺ + 2MnO₄⁻ + 5C₂O₄⁻² → 10CO₂ + 2Mn²⁺ + 8H₂O

4 0

4 years ago