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FromTheMoon [43]

2 years ago

15

Which metal does not form cations of differing charges?

1 answer:

valkas [14]2 years ago

8 0

Transition metals

Most transition metals differ from the metals of Groups 1, 2, and 13 in that they are capable of forming more than one cation with different ionic charges. As an example, iron commonly forms two different ions

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What is the shape of a molecule containing three covalent bonds with one unshared pair?

Schach [20]

pyramidal, if you have a molecule kit, i would strongly recommend watching a video of someone using a kit explaining the different shapes and following along. It helps a lot!

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2 years ago

According to Bernoulli's Principle, slower moving fluids exert ____________ pressure than faster moving fluids. (Fill in the bla

Mariana [72]

According to Bernoulli's Principle, slower moving fluids exert a lower or decreased pressure than faster moving liquids.

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2 years ago

WILL GIVE BRAINLIEST FOR THE RIGHT ANSWER!!!!!Which elements can form diatomic molecules joined by a single covalent bond?

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Answer:

b

Explanation:

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2 years ago

Describe two shortcomings of the pennium model for isotopes

umka21 [38]

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3 years ago

Wastewater from a cement factory contains 0.280 g of Ca2+ ion and 0.0220 g of Mg2+ ion per 100.0 L of solution. The solution den

faltersainse [42]

<u>Answer:</u> The concentration of $Ca^{2+}\text{ and }Mg^{2+}$ ions are 2.797 ppm and 0.212 ppm respectively.

<u>Explanation:</u>

To calculate the mass of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Volume of gold = 100 L = 100000 mL (Conversion factor: 1 L = 1000 mL)

Density of gold = 1.001 g/mL

Putting values in above equation, we get:

$1.001g/mL=\frac{\text{Mass of solution}}{100000mL}\\\\\text{Mass of solution}=1.001\times 10^5g$

To calculate the concentration in ppm (by mass), we use the equation:

$ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6$

<u>Calculating the concentration of calcium ions:</u>

Mass of $Ca^{2+$ ions = 0.280 g

Putting values in above equation, we get:

$ppm(Ca^{2+})=\frac{0.280g}{1.001\times 10^5}\times 10^6=2.797ppm$

<u>Calculating the concentration of magnesium ions:</u>

Mass of $Mg^{2+$ ions = 0.0220 g

Putting values in above equation, we get:

$ppm(Mg^{2+})=\frac{0.0220g}{1.001\times 10^5}\times 10^6=0.212ppm$

Hence, the concentration of $Ca^{2+}\text{ and }Mg^{2+}$ ions are 2.797 ppm and 0.212 ppm respectively.

7 0

3 years ago