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FinnZ [79.3K]
3 years ago
5

Simplify the radical the square root of 81 d^6

Mathematics
2 answers:
Alexxandr [17]3 years ago
5 0

Answer:

<h2>9y3</h2>

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Kaylis [27]3 years ago
4 0

Can not be simplify

Step-by-step explanation:

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What is the equation of a line that has a y-intercept of 4 and an x-intercept of -2?​
Furkat [3]

Answer:

y = 2x + 4

Step-by-step explanation:

Two points on this line are (-2, 0) and (0, 4).  Going from the first to the second, x increases by 2 (this is the 'run') and y increases by 4 ('rise').

Thus, the slope of this line is m = rise / run =  4/2 = 2

Using the slope-intercept formula, we get y = mx + b = 2x + b

Let x = -2 and y = 0 to find b:  0 = 2(-2) + b, so b = 4, and the desired equation is then:

y = 2x + 4

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3 years ago
A blank is a unit rate with a denominator of 1 unit. What is the the blank?
Bumek [7]

A unit rate is a ratio that has a denominator of 1. A unit rate is also called a unit ratio. (They mean the same thing.)

\frac{5}{4} and 3:8 and 40\mbox{ to }10 are ratios, but they are not unit ratios.

\frac{1.25}{1} and 0.375:1 and 4\mbox{ to }1 are unit ratios.

Any ratio can be converted into a unit ratio by dividing the numerator and the denominator by the denominator.


4 0
3 years ago
Find the perimeter of WXYZ. Round to the nearest tenth if necessary.
yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

W(-1, 1) = (x_1, y_1)

X(1, 2) = (x_2, y_2)

Plug in the values

WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}

WX = \sqrt{(2)^2 + (1)^2}

WX = \sqrt{4 + 1}

WX = \sqrt{5}

WX = 2.24

✔️Distance between X(1, 2) and Y(2, -4)

Let,

X(1, 2) = (x_1, y_1)

Y(2, -4) = (x_2, y_2)

Plug in the values

XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}

XY = \sqrt{(1)^2 + (-6)^2}

XY = \sqrt{1 + 36}

XY = \sqrt{37}

XY = 6.08

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

Y(2, -4) = (x_1, y_1)

Z(-2, -1) = (x_2, y_2)

Plug in the values

YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}

YZ = \sqrt{(-4)^2 + (3)^2}

YZ = \sqrt{16 + 9}

YZ = \sqrt{25}

YZ = 5

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

Z(-2, -1) = (x_1, y_1)

W(-1, 1) = (x_2, y_2)

Plug in the values

ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}

ZW = \sqrt{(1)^2 + (2)^2}

ZW = \sqrt{1 + 4}

ZW = \sqrt{5}

ZW = 2.24

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

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3 years ago
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Akimi4 [234]

Answer:

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Step-by-step explanation:

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My number has 2 hundreds, the tens digit has 9 more than the ones digit
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The number is two hundred ninety- one. 
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