Simple interest formula
Interest = Pit = $50
P=principal (initial investment)
i=annual interest rate = 0.04
t=time in years = 6 months = 0.5 years
Substitute values,
$50 = P*0.04*0.5 
Solve for P
P=$50/(0.04*0.5)=$2500
        
             
        
        
        
Answer:
median: 10 <h <13
mean: 12.12
Step-by-step explanation:
 
        
             
        
        
        
With what because I cannot see the math or any subject of the answer you need
        
             
        
        
        
The composite shape is made up of a cube with a side length of 5 inches and a cylinder with a radius of 2 inches and a height of 4 inches.
The composite solid's surface area is 225.4 square inches.
Step-by-step explanation:
Step 1:
The given composite shape is made up of a cube with a side length of 5 inches and a cylinder with a radius of 2 inches and a height of 4 inches.
The surface area of the composite shape is given by summing the individual surface areas.
The composite shape's surface area = The cube's surface area + the cylinder's surface area.
Step 2: 
Any cube's surface area is calculated by multiplying 6 with the square of the side length (
).
The cube's surface area = 
 = 
 = 
 square inches.
Step 3:
Any cylinder's surface area is calculated with the following formula;
The cylinder's surface area = 
 = 
 = 
 square inches
Step 4:
The composite shape's surface area = The cube's surface area + the cylinder's surface area.
The composite shape's surface area = 150 + 75.398 = 225.398 square inches. Rounding this off, we get the area as 225.4 square inches.
 
        
             
        
        
        
Answer:
see explanation
Step-by-step explanation:
Check the value of the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real
• If b² - 4ac = 0 roots are real and equal
• If b² - 4ac < 0 then roots are not real
given (x - a)(x - b) = k² ( expand factors )
x² - bx - ax - k² = 0 ( in standard form )
x² + x(- a - b) - k² = 0
with a = 1, b = (- a - b), c = -k²
b² - 4ac = (- a - b)² + 4k² 
For a, b, k ∈ R then (- a - b)² ≥ 0 and 4k² ≥ 0
Hence roots of the equation are always real for a, b, k ∈ R