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2 years ago

What eventually happens to a gas if its pressure is increased?

Chemistry

1 answer:

gulaghasi [49]2 years ago

3 0

Answer:

According to Boyle's law pressure of a particular amount of gas is inversely proportional to the volume of the gas. So, when we increase the pressure of the gas the volume of the gas decrease and the gas start to condense.

Explanation:

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Choose the substance with the highest surface tension.

umka2103 [35]

Answer:

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3 years ago

A neutral pH level is _____.<br> 5<br> 7<br> 8

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3 years ago

Calculate the standard free-energy change at 25 ∘C for the following reaction:

lianna [129]

Answer:

Standard free-energy change at $25^{0}\textrm{C}$ is $-3.80\times 10^{2}kJ/mol$

Explanation:

Oxidation: $Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)$

Reduction: $Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)$

--------------------------------------------------------------------------------------

Overall: $Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)$

Standard cell potential, $E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}$

So, $E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V$

We know, standard free energy change at $25^{0}\textrm{C}$ ( $\Delta G^{0}$ ): $\Delta G^{0}=-nFE_{cell}^{0}$

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, $\Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol$

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3 years ago

Read 2 more answers

HELPP please I’ll mark you as brainlister it’s 100 points

Andrei [34K]

Answer:

Explanation:

hope this helps, can i have brainliest

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2 years ago

Someone help me with this please

fiasKO [112]

The anwser I generated was “B”

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3 years ago