Answer: hello your question is incomplete attached below is the complete question
answer : 1/2 KD^2 ( option A )
Explanation:
P.E ( potential energy ) = mgd
In case 1 P.E = 0 i.e. mgd = 0
Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring
<u>The potential energy of the M in case 2 </u>
= P.E of M at rest + P.E of the spring
= 0 + 1/2 KD^2
The naturally occurring radioisotope which is used as the fuel for a nuclear reactor is the Uranium-235. It has been said that one kilogram of Uranium-235 can theoretically male about 20 terajoules of energy when used as a fuel for power plants.
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Answer:
energy transform mechanical to motion