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SCORPION-xisa [38]
3 years ago
15

An object is moving in the absence of a net force. Which of the following best describes the object’s motion? A. The object will

slow down at a constant rate until coming to rest B. The object will stop moving and remain at rest until acted on by a net force C. The object will continue to move at a constant speed but in a circular path D. The object will continue to move with a constant velocity
Physics
1 answer:
docker41 [41]3 years ago
3 0

Answer:

D. The object will continue to move with a constant velocity

Explanation:

According to Newton's first law also known as law of inertia, states that an object at rest will remain at rest or, if in motion, will remain in motion at constant velocity unless acted on by a net external force.

Therefore, An object moving in the absence of a net force will continue to move at a constant velocity

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Answer:

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Explanation:

Compared to Jupiter, Saturn's atmosphere is more calm with fewer disturbances or storms.

The Atmosphere in Jupiter is highly violent and thinner as compared with Saturn.

The layers of atmosphere on Saturn is thicker because of lower gravity of Saturn and hence they are calmer.  

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What is the force of an object with a mass of 65 kg and an an unknown acceleration?
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F = 65 * a

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1. A small package is dropped from the Golden Gate Bridge. What is the velocity of the package
Sidana [21]

The velocity of the package  after it has fallen for 3.0 s is 29.4 m/s

From the question,

A small package is dropped from the Golden Gate Bridge.

This means the initial velocity of the package is 0 m/s.

We are to calculate the velocity of the package  after it has fallen for 3.0 s.

From one of the equations of kinematics for objects falling freely,

We have that,

v = u + gt

Where

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

and t is time

To calculate the velocity of the package  after it has fallen for 3.0 s

That means, we will determine the value of v, at time t = 3.0 s

The parameters are

u = 0 m/s

g = 9.8 m/s²

t = 3.0 s

Putting these values into the equation

v = u + gt

We get

v = 0 + (9.8×3.0)

v = 0 + 29.4

v = 29.4 m/s

Hence, the velocity of the package  after it has fallen for 3.0 s is 29.4 m/s

Learn more here: brainly.com/question/13327816

6 0
2 years ago
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