Answer:
Because the ball is dropped, we are going to assume its initial velocity is 0. With that said, acceleration is essentially the change in the velocity versus the change in time, hence the unit m/s^2, which can be thought of as “meters per second per second.” The only force acting on the ball is gravity.
That being said, you can simply divide the change in velocity by the change in time, giving you an answer of 9.8 m/s^2, which is the value of g. Even if they did not give you a time, the answer would still always be the value of g (that is if the question pertains to earth), as acceleration due to gravity is a constant.
Explanation:
Please mark brainliest
Very funny. Can I do all your homework for you?
To find out the weight of the object, you'll need to slide the weight poises until the pointer is at zero again. Start with the two heavier weight poises and then use the lightest one to do the fine tuning. Our triple beam balance and the Ohaus triple beam balance are accurate to 0.1 grams.
Answer:
V₂ = 0.4432
Explanation:
The normalize procedure is widely used in science, in this case we are going to normalize to the voltage value that exists 4 cm away
Vₙ= V_{measured} / V₀
where the voltage at the desired distance is V₀ = 185 mV = 0.185 V
the normalized voltage are
forr x = 4 cm
V₁ = 185/185
V₁ = 1
for x = 6.2 cm
V₂ = 82/185
V₂ = 0.4432
