Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
Seven units long. The distance between 2 sides, in this example is 6, and -1. The distance between 6 and -1 is 7, so when you add units, you get 7 units.
Answer:
the terms are 400n , 62n 120 and 8n
the number of coefficients is 3
equa expression is 346n+120
Step-by-step explanation:1
Combining like terms 400n400n and -62n−62n
338n+120+8n
338n+120+8n
2 Combining like terms 338n338n and 8n8n
346n+120
346n+120
For the rest of them i just counted.
You can choose to answer this with fractions or decimals. I'll choose fractions because we won't need calculators. 22 1/2 miles "in" 1/3 hour, means 22 1/2 mi divided by 1/3 hour.
22 1/2 = [(22×2) + 1] ÷ 2 = 45/2
So (45/2)mi ÷ (1/3)hr is the same as (45/2) × (3/1), or (45×3)/2 = 135/2, which is 67 1/2, or 67.5 mi/hr (mph).
